To find AC, you need to add the lengths of segments BC and CD together. If BC is 7 and CD is 24, then AC = BC + CD = 7 + 24 = 31. Therefore, AC is 31 units long.
The probability of ac and bc is 1/5.
To find the length of side AC in a triangle, you can use the Law of Cosines if you know the lengths of the other two sides (AB and BC) and the included angle (∠B). The formula is: [ AC^2 = AB^2 + BC^2 - 2 \times AB \times BC \times \cos(\angle B) ] After calculating AC², take the square root to find AC. If you have a right triangle, you can simply use the Pythagorean theorem: [ AC = \sqrt{AB^2 + BC^2} ] (assuming AC is the hypotenuse).
36
yes because ab plus bc is ac
Assuming that AB and AC are straight lines, the answer depends on the angle between AB and AC. Depending on that, BC can have any value in the range (22, 46).
I believe it means Before
ac is After Christ and bc is Before Christ
It is possible, depending on what on earth AC and BC are!
We can use the identity ((a + b + c)^2 = a^2 + b^2 + c^2 + 2(ab + ac + bc)). Given that (a + b + c = 12) and (a^2 + b^2 + c^2 = 64), we can substitute these values into the identity: [ 12^2 = 64 + 2(ab + ac + bc). ] Calculating (12^2) gives us 144, so: [ 144 = 64 + 2(ab + ac + bc). ] Subtracting 64 from both sides gives us: [ 80 = 2(ab + ac + bc). ] Dividing by 2, we find: [ ab + ac + bc = 40. ] Thus, the value of (ab + ac + bc) is 40.
A+BC+AC+B=A+BC+AC+B unless any of these variables has an assigned value.
Find the length of each sideside ab and bc differ in length by 10cm and the side ac and bc differ in length 3cmfind the lenght of each sideperimeter of a triangle abc is 103cm?