(a - 5b)(c - 5d)
You cannot prove it since it is not true for a general quadrilateral.
In this case you want to group the terms so they have at least two terms in common. First step group and rewrite it: abc + a'bc + a'b'c' + a'b'c + ab'c' + abc' = Use the rule Identities x(y+z)=xy+xz: bc(a+a') + a'b'(c'+c) + ac'(b'+b) = Use the rule Identities x+x'=1: bc (1) + a'b'(1) + ac'(1) = Use the rule Identities x(1) = x: bc+a'b'+ac'
6(b - ac + b2 - bc)
15 units
never A+ :))
5
The distributive property states that a(b + c) = ab + ac. This only works in your case if you meant to write 15(x + 20). That would equal 15x + 300.
yes because ab plus bc is ac
x(x - 1)(4x - 15)
15 ac + 20 bc + 6 ad + 8 bd =3a (5c + 2d) + 4b (5c + 2d) =(3a + 4b) (5c + 2d)
You could conclude that B lies between A and C.
associative? single replacement
Alternator and ac generator is equal
A+BC+AC+B=A+BC+AC+B unless any of these variables has an assigned value.
An offset AC wave. It will be offset by the magnitude of the DC applied.
(a + b)(b + c)