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If cos and theta 0.65 what is the value of sin and theta?
Remember use the Pythagorean Trig/ Identity. Sin^(2)(Theta) + Cos^(2)(Theta) = 1 Algebraically rearrange Sin^(2)(Theta) = 1 - Cos^(2)(Theta) Substitute Sin^(2)(Theta) = 1 - 0.65^(2) Factor Sin^(2)(Theta) = ( 1- 0.65 )( 1 + 0.65) Sin^(2)(Theta) = (0.35)(1.65) Sin^(2)(Theta) = 0.5775 Sin(Theta) = sqrt(0.5775) Sin(Theta) = 0.759934207.... Theta = Sun^(-1)(0.759934207...) Theta = 49.45839813 degrees.
What is the value of theta if 4sin theta is equal to 2?
4 sin(theta) = 2 => sin(theta) = 2/4 = 0.5. Therefore theta = 30 + k*360 degrees or 150 + k*360 degrees where k is any integer.
What does negative sine squared plus cosine squared equal?
To determine what negative sine squared plus cosine squared is equal to, start with the primary trigonometric identity, which is based on the pythagorean theorem...sin2(theta) + cos2(theta) = 1... and then solve for the question...cos2(theta) = 1 - sin2(theta)2 cos2(theta) = 1 - sin2(theta) + cos2(theta)2 cos2(theta) - 1 = - sin2(theta) + cos2(theta)
What is the sin theta of 30 degrees?
Sin theta of 30 degrees is1/2
How do you convert this polar equation r2 sin 2 theta equals 8 to cartesian form?
It's possible
What is cot theta 1.5 sin theta?
The expression "cot theta = 1.5 sin theta" can be rewritten using the definitions of trigonometric functions. Since cotangent is the reciprocal of tangent, we have cot(theta) = cos(theta) / sin(theta). Therefore, the equation becomes cos(theta) / sin(theta) = 1.5 sin(theta), leading to cos(theta) = 1.5 sin^2(theta). This relationship can be used to find specific values of theta that satisfy the equation.
If cos and theta 0.65 what is the value of sin and theta?
Remember use the Pythagorean Trig/ Identity. Sin^(2)(Theta) + Cos^(2)(Theta) = 1 Algebraically rearrange Sin^(2)(Theta) = 1 - Cos^(2)(Theta) Substitute Sin^(2)(Theta) = 1 - 0.65^(2) Factor Sin^(2)(Theta) = ( 1- 0.65 )( 1 + 0.65) Sin^(2)(Theta) = (0.35)(1.65) Sin^(2)(Theta) = 0.5775 Sin(Theta) = sqrt(0.5775) Sin(Theta) = 0.759934207.... Theta = Sun^(-1)(0.759934207...) Theta = 49.45839813 degrees.
What is sin theta cos theta?
It's 1/2 of sin(2 theta) .
How do you solve 2 sin squared theta equals one fourth?
2 sin^2 theta = 1/4 sin^2 theta = 1/8 sin theta = sqrt(1/8) theta = arcsin(sqrt(1/8))
What is the value of theta if 4sin theta is equal to 2?
4 sin(theta) = 2 => sin(theta) = 2/4 = 0.5. Therefore theta = 30 + k*360 degrees or 150 + k*360 degrees where k is any integer.
What does 2sin squared theta equal and why?
It is 2*sin(theta)*sin(theta) because that is how multiplication is defined!
What does negative sine squared plus cosine squared equal?
To determine what negative sine squared plus cosine squared is equal to, start with the primary trigonometric identity, which is based on the pythagorean theorem...sin2(theta) + cos2(theta) = 1... and then solve for the question...cos2(theta) = 1 - sin2(theta)2 cos2(theta) = 1 - sin2(theta) + cos2(theta)2 cos2(theta) - 1 = - sin2(theta) + cos2(theta)
How do you solve sin2 theta equals 0.75?
To solve the equation (\sin^2 \theta = 0.75), first take the square root of both sides to get (\sin \theta = \pm \sqrt{0.75} = \pm \frac{\sqrt{3}}{2}). Then, find the angles (\theta) for which (\sin \theta = \frac{\sqrt{3}}{2}) and (\sin \theta = -\frac{\sqrt{3}}{2}). The solutions are (\theta = \frac{\pi}{3} + 2k\pi) and (\theta = \frac{2\pi}{3} + 2k\pi) for the positive case, and (\theta = \frac{7\pi}{6} + 2k\pi) and (\theta = \frac{4\pi}{3} + 2k\pi) for the negative case, where (k) is any integer.
What is the sin theta of 30 degrees?
Sin theta of 30 degrees is1/2
How do you convert this polar equation r2 sin 2 theta equals 8 to cartesian form?
It's possible
Why is 2 sin theta cos theta equal to sin 2theta?
because sin(2x) = 2sin(x)cos(x)
Write the curve x3 y3 3axy in polar form Hence find the area encircled by its loop?
To convert the curve (x^3 + y^3 = 3axy) into polar form, we use the substitutions (x = r\cos\theta) and (y = r\sin\theta). This gives us the polar equation (r^3(\cos^3\theta + \sin^3\theta) = 3ar^2\cos\theta\sin\theta), which simplifies to (r = \frac{3a\cos\theta\sin\theta}{\cos^3\theta + \sin^3\theta}). To find the area encircled by the loop, we can use the formula for the area in polar coordinates, (A = \frac{1}{2} \int_{\theta_1}^{\theta_2} r^2 d\theta). Evaluating this integral over one loop (typically from (0) to (\frac{\pi}{2}) for the symmetric shape) yields the area (A = \frac{3\pi a^2}{8}).
