(/) = theta
sin 2(/) = 2sin(/)cos(/)
4Sin(theta) = 2 Sin(Theta) = 2/4 = 1/2 - 0.5 Theta = Sin^(-1) [0.5] Theta = 30 degrees.
-Sin^(2)(Theta) + Cos^(2)Theta => Cos^(2)Theta - Sin^(2)Theta Factor (Cos(Theta) - Sin(Theta))( Cos(Theta) + Sin(Theta)) #Is the Pythagorean factors . Or -Sin^(2)Theta = -(1 - Cos^(2)Theta) = Cos(2)Theta - 1 Substitute Cos^(2)Thetqa - 1 + Cos^(2) Theta = 2Cos^(2)Theta - 1
Sin theta of 30 degrees is1/2
It's possible
Since theta is in the second quadrant, sin(theta) is positive. sin2(theta) = 1 - cos2(theta) = 0.803 So sin(theta) = +sqrt(0.803) = 0.896.
It's 1/2 of sin(2 theta) .
2 sin^2 theta = 1/4 sin^2 theta = 1/8 sin theta = sqrt(1/8) theta = arcsin(sqrt(1/8))
4Sin(theta) = 2 Sin(Theta) = 2/4 = 1/2 - 0.5 Theta = Sin^(-1) [0.5] Theta = 30 degrees.
It is 2*sin(theta)*sin(theta) because that is how multiplication is defined!
-Sin^(2)(Theta) + Cos^(2)Theta => Cos^(2)Theta - Sin^(2)Theta Factor (Cos(Theta) - Sin(Theta))( Cos(Theta) + Sin(Theta)) #Is the Pythagorean factors . Or -Sin^(2)Theta = -(1 - Cos^(2)Theta) = Cos(2)Theta - 1 Substitute Cos^(2)Thetqa - 1 + Cos^(2) Theta = 2Cos^(2)Theta - 1
Sin theta of 30 degrees is1/2
It's possible
because sin(2x) = 2sin(x)cos(x)
[]=theta 1. sin[]=0.5sin[] Subtract 0.5sin[] from both sides.2. 0.5sin[]=0. Divide both sides by 0.5.3. Sin[] =0.[]=0 or pi (radians)
To convert the curve (x^3 + y^3 = 3axy) into polar form, we use the substitutions (x = r\cos\theta) and (y = r\sin\theta). This gives us the polar equation (r^3(\cos^3\theta + \sin^3\theta) = 3ar^2\cos\theta\sin\theta), which simplifies to (r = \frac{3a\cos\theta\sin\theta}{\cos^3\theta + \sin^3\theta}). To find the area encircled by the loop, we can use the formula for the area in polar coordinates, (A = \frac{1}{2} \int_{\theta_1}^{\theta_2} r^2 d\theta). Evaluating this integral over one loop (typically from (0) to (\frac{\pi}{2}) for the symmetric shape) yields the area (A = \frac{3\pi a^2}{8}).
If sin (theta) is 3/5, then sin2 (theta) is (3/5)2, or 9/25.
Since theta is in the second quadrant, sin(theta) is positive. sin2(theta) = 1 - cos2(theta) = 0.803 So sin(theta) = +sqrt(0.803) = 0.896.