Pythagoras! x-axis difference is 7 units, y-axis difference is 7 units, so distance is sqrt(7^2 + 7^2) ie sqrt 98 = 9.9 to first significant figure.
true
the distance between two points is length
Use Pythagoras to find the distance between two points (x0,.y0) and (x1, y1): distance = √(change_in_x² + change_in_y²) → distance = √((x1 - x0)² + (y1 - y0)²) → distance = √((4 - 1)² + (-1 -2)²) → distance = √(3² + (-2)²) → distance = √(9 + 9) → distance = √18 = 3 √2
Points: (2, 2) and (8, -6) Distance: 10
If you mean points of (-4, 2) and (1, 2) then the distance works out as 5
Points: (2, 1) and (14, 6) Distance: 13
0 0
8.54
10
If the points are (3, 2) and (9, 10) then the distance works out as 10
the distance between two points is length
The distance between the points of (4, 3) and (0, 3) is 4 units
11 points
Points: (-6, 1) and (-2, -2) Distance: 5 units
Use Pythagoras to find the distance between two points (x0,.y0) and (x1, y1): distance = √(change_in_x² + change_in_y²) → distance = √((x1 - x0)² + (y1 - y0)²) → distance = √((4 - 1)² + (-1 -2)²) → distance = √(3² + (-2)²) → distance = √(9 + 9) → distance = √18 = 3 √2
Points: (2, 2) and (8, -6) Distance: 10
The 3-D distance formula depends upon what the two points are that you are trying to find the distance between. In order to find the formula, you need to enter 2 sets of coordinates in the 3 dimensional Cartesian coordinate system, and then calculate the distance between the points.
length