Call the smaller of the two consecutive integers n. Then, from the problem statement:
n(n+2) = 168, or n2 + 2n - 168 = 0, or (n + 14)(n - 12) = 0, which is true when n = -14 or +12. Therefore, the two integers sought are 12 and 14.
I think you mean consecutive even integers: 20 & 22
The product of 2 consecutive positive number is 48. Find the 2 numbers
The sum of the squares of two consecutive positive even integers is 340. Find the integers.
There are no two consecutive even integers, consecutive odd integers, or consecutive integers that satisfy that relationship.
No. There is no set of three consecutive even integers with a sum of 40.
The numbers are 82, 84, 86 and 88.
-4, -2, 0, and 2 are the four consecutive even integers. When you add them up they equal -4.
The numbers are 6 and 8.
It will alway be even, because it will always be the product of an odd and an even number, which is always even.
The integers are 41, 42 and 43. Also, using consecutive even integers, you find: 40, 42 and 44.
The two consecutive, even integers are 350 and 352.
No.The sum of any number of even integers, consecutive or not, MUST be even. 219 is not even.No.The sum of any number of even integers, consecutive or not, MUST be even. 219 is not even.No.The sum of any number of even integers, consecutive or not, MUST be even. 219 is not even.No.The sum of any number of even integers, consecutive or not, MUST be even. 219 is not even.
The even integers are 22, 24 and 26.
There are no consecutive even integers totaling 123 but there are two combinations of odd/even integers. They are 39, 41 and 43 as well as 40, 41 and 42.
The sum of two consecutive odd integers is an even number. There is no possible answer to this question.
Half it = 41, so consecutive even integers are 40 & 42
The three integers are 25, 26, and 27.
There are no "two consecutive integers" that can do that.But there are two consecutive even integers that can: 8 and 10 .
The integers are -37, -36 and -35. Also, using consecutive even integers: -38, -36 and -34.