There are 8 letters in "geometry", so there are 8! (factorial) ways to arrange them in different permutations.
8! = 40,320 permutations.
360; I think.
239,500,800 12!/2! * * * * * Actually, as the word "permutation" [not permutations] has 11 letters, the answer is 11!/2! = 19,958,400
Any string of two letters.
Permutation City has 310 pages.
The word "numbers" consists of 7 distinct letters. The number of permutations of these letters is calculated using the factorial of the number of letters, which is 7!. Therefore, the total number of permutations is 7! = 5,040.
geometry has 8 letters, 2 of which are the same (e) So, the answer is 8!/2! = 20,160
permutation without replacement
Coniohser has 9 letters. So the solution is permutation of nine that means 1*2*3*4*5*6*7*8*9 =362880
pis
The question contradicts itself. The order of the letters is irrelevant in a combination [though it does matter in a permutation]. So what is it that you are asking for? Combinations or order-dependent arrangements?
i am a permutation is a awesome answer
Normally, there would be 5!=120 different permutations* of five letters. Since two of the letters are the same, we can each of these permutations will be duplicated once (with the matching letters switched). So there are only half as many, or 60 permutations.* (the correct terminology is "permutation". "combination" means something else.)