Study guides

☆☆

Q: How are the areas of similar rectangles related to the scale factor?

Write your answer...

Submit

Related questions

Rectangles are related to the distributive property because you can divide a rectangle into smaller rectangles. The sum of the areas of the smaller rectangles will equal the area of the larger rectangle.

I guess you mean the ratio of the areas; it depends if the 2 rectangles are "similar figures"; that is their matching sides are in the same ratio. If they are similar then the ratio of their areas is the square of the ratio of the sides.

The areas are related by the square of the scale factor.

For areas: Square the Scale Factor.

When the can be added or subtracted evenly

The areas will be proportional to (scale)2

rddffdg

the are gets that many times smaller.

The ratio of any two corresponding similar geometric figures lengths in two . Note: The ratio of areas of two similar figures is the square of the scale factor. The ratio of volumes of two similar figures is the cube of the scale factor. .... (: hope it helped (: .....

The ratio of their perimeters is also 45/35 = 9/7. The ratio of their areas is (9/7)2 = 81/63

In biogeography studies, similar animals that seem to be closely related are adapted to different environments in nearby areas. Also, in areas that are widely separated animals that seem to be unrelated are observed to have similar adaptations to similar environments in the separate areas.

If the sides of two shapes have a scale factor of sf:1, then their areas will be in the ratio of sf2: 1.

An L-shaped area can be divided into two rectangles. The total area is the sum of the areas of the two rectangles.

Find the areas of the rectangles and triangles. Add them together.

I can give the width of one of the rectangles. The first rectangle of area 15 cm2 and length of 5 cm has width of 3 cm. It is impossible to know the width of the other rectangle of area 60 cm2. However, if you had said that the two rectangles were similar, then the dimensions of the second rectangle would be 10 cm X 6 cm. But you didn't say that the two rectangles were similar; so there are infinite possibilities of what the dimensions of the second rectangle might be.

You could consider the cross as two intersecting rectangles. Calculate the area of both rectangles and the area of the intersection (overlap). Then area of cross = sum of the areas of the rectangles minus the area of the overlap.

Their scale factor is 3 : 5, which mean their sides scale factor is 3 : 5, too. The area formula : S = bh/2 ---> The ratio of their areas : (3 : 5)^2=9 : 25 It's the answer.

Whatever the ratio of perimeters of the similar figures, the areas will be in the ratios squared. Examples: * if the figures have perimeters in a ratio of 1:2, their areas will have a ratio of 1²:2² = 1:4. * If the figures have perimeters in a ratio of 2:3, their areas will have a ratio of 2²:3² = 4:9.

The area of a parallelogram is twice that of the two triangles that are formed by the line transecting it. (Sort of like finding out how many cows you have by counting eyes and dividing by two.)

It is 21/23.

Assuming you have the dimensions of each of the sides - treat it as two separate rectangles. Using the measurements you have, work out the areas of both rectangles - then add them together.

With similar objects (where one is an exact scale version of the other) then if the linear measurements are in the ratio 2 : 3 then the areas are in the ratio 22 : 32 which equals 4 : 9. So if the sides of two triangles have a scale factor of 2/3 then the areas have a scale factor of 4/9.

Yes they are similar.

The most famous push and pull factor in European history was that related to the Industrial Revolution. People were pushed off rural areas and farmland and pushed into urban areas and factories.

Yes. Say there are two rectangles, both with perimeter of 20. One of the rectangles is a 2 by 8 rectangle. The area of this rectangle is 2 x 8 which is 16. The other rectangle is a 4 by 6 rectangle. It has an area of 4 x 6 which is 24.