3x^(2) + 24x = 0
Divide by '3'
x^(2) + 8 = 0
x^(2) = - 8
x = sqrt(-8) Yjis is NOT resolved as you cannot take the squate root of a negative number, without going into IMAGINARY numbers.
x = sqrt( -1 X 8)
x = sqrt(-1) X sqrt(8)
x= sqrt(-1) X 2sqrt(2)
Sqrt(-1) is shown as 'i' ( small/lower case 'i' , algebraically).
Hence
x = 2sqrt(2) i
16? using 16, you have (3x2 + 4)(3x2 + 4) = 9x2 + 24x + 16
3x2 + 17x + c = 0, rearranging gives c = -3x2 - 17x
3x2-24x-48 is not factorable.
This is an expression and you do not solve an expression, but you can factor this one.X2 + 3X4X2(1 + 3X2)========
3x2 + x - 2 = 0(3x - 2) (x + 1) = 0x = + 2/3x = -1
No real roots.
3(2) + 24x + 48 = 0 6 + 24x + 48 = 0 24x + 54 = 0 24x + 54 - 54 = 0 - 54 24x = -54 24x/24 = -54/24 x = -9/4 x = -2 1/4
16? using 16, you have (3x2 + 4)(3x2 + 4) = 9x2 + 24x + 16
3x2 + 17x + c = 0, rearranging gives c = -3x2 - 17x
3x2-24x-48 is not factorable.
3x^(2) - 24x + 48 Factor out '3' 3(x^(2) - 8x + 16) 3(x - 4)(x - 4) Fullt factored.
By using the quadratic equation formula which will work out as: x = 4- the square root of 32 and x = 4+the square root of 32
y = 3x^(2) + 24x - 1 Differentiate and equate to '0' dy/dx = 6x - 24 = 0 6x - 24 = 0 6x = 24 x = 4 is the line of symmetry.
3x2=6+38=44
-3x2 + 22x = 0 You start by dividing both sides by x: ∴ -3x + 22 = 0 Then rearrange to solve for x: ∴3x = 22 ∴ x = 7 + 1/3
6x(3x2 - x + 4)
GCF = 12x.24x = 2(12x)36x3 = 3x2(12x)