You can do this by finding two numbers that add to make 18 (the coefficient of the middle term) and multiply to make 65 (the product of the first term's coefficient and the last term).
As it happens, 65 only has two factors, 5 and 13, which do add up to make 18. Unfortunately, they won't work for this equation, as we need them to add up to 18, and multiply to make negative 65. So this statement can not be factored.
x3 + x2 + 4x + 4 = (x2 + 4)(x + 1)
x + 4
x2(x3 + 1) is the best you can do there.
Factor x2 plus 12xp plus 36p2 is (x+6p)(x+6p).
That does not factor neatly.
You can't factor it
Not factorable
1
x2 + 5x - 120 can not be factored.
x2+10x-336
x2 - 13 + 30 = x2 + 17, which has no real factors.
x2 + 7x + 6 = (x + 6) (x + 1)