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You can do this by finding two numbers that add to make 18 (the coefficient of the middle term) and multiply to make 65 (the product of the first term's coefficient and the last term).
As it happens, 65 only has two factors, 5 and 13, which do add up to make 18. Unfortunately, they won't work for this equation, as we need them to add up to 18, and multiply to make negative 65. So this statement can not be factored.
What else can I help you with?
What is the factor of x3 plus x2 plus 4x plus 4?
x3 + x2 + 4x + 4 = (x2 + 4)(x + 1)
What binomial is a factor of this trinomial x2 plus 8x plus 16?
x + 4
Factor x5 plus x2?
x^(5) + x^(2)= x^(2) ))x^(3) + 1) Think of '1' as '1^(3)' Hence x^(2)(x^(3) + 1^(3)) x^(2)(x + 1)(x^(2) - x + 1^(2)) or x^(2)(x + 1)(x^(2) - x + 1) Done!!!!!
How do you factor x2 plus 12xp plus 36p2?
Factor x2 plus 12xp plus 36p2 is (x+6p)(x+6p).
How do you factor x2 plus 15x-1?
You can't factor it
Does this have a factor x2-8x plus 6?
That does not factor neatly.
Factor x2 plus 7x plus 10?
1
Factor X2 plus 6X plus 4?
Not factorable
Factor x2 plus 5x-120?
x2 + 5x - 120 can not be factored.
How can I factor this term x2 plus 10x-336?
x2+10x-336
How can you factor x2-13 plus 30?
x2 - 13 + 30 = x2 + 17, which has no real factors.
How do you factor x2 plus 7x plus 6?
x2 + 7x + 6 = (x + 6) (x + 1)
