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2b=6squared, and 6x6=36
To factor the expression 3ab + 3ac + 2b^2 + 2bc, we first look for common factors among the terms. We can factor out a 3a from the first two terms, and a 2 from the last two terms. This gives us 3a(b + c) + 2(b^2 + bc). Next, we notice that we can factor out a b from the second term in the second parenthesis, giving us the final factored form: 3a(b + c) + 2b(b + c).
Presumably this is an equation in the form of: b+2b-11 = 88 3b = 88+11 3b = 99 b = 33 However, if this was b exponent 2 (squared) or b^2 for the first b, then it is a quadratic expression. b^2 + 2b - 11 = 88 b^2 + 2b - 99 = 0 (b+11)(b-9) = 0 B = -11 or 9
The GCF is a^2b
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