5ab(3a - 2b)
-2
(a2 + 2)(b + 3)
9a4-b2=36a-2b=2(18-b) But if you meant 9a^4-b^2 it is not possible to factor
Assuming the missing sign is "minus" then you have the difference between two squares. This is solved as (x + y)(x - y). In your example x = 4a and y = 2b so the factorisation is (4a + 2b)(4a - 2b) or more completely: (4)(2a + b)(2a - b).
(a + 2b)(a + 2b)
(2b - 5)(b + 7)
5a(a+2b+b²)
3ab + 3ac + 2b2 + 2bc = 3a(b + c) + 2b(b + c) = (3a + 2b)(b + c)
(a + 2b)(c + 2d)
4(a + 2b - 4c)
The Answer to this question is 9 (2B+4) and (1B+3)
3a(b+c)+2b(b+c)
(a - 2b)(c - 3d)
ac - 3ad - 2bc + 6bd = a(c - 3d) - 2b(c - 3d) = (a - 2b)(c - 3d)
ac + 2ad + 2bc + 4bd = a(c + 2d) + 2b(c + 2d) = (a + 2b)(c + 2d) Now expand to confirm your answer: c(a + 2b) + 2d(a + 2b) = ac + 2bc + 2ad + 4bd ≡ ac + 2ad + 2bc + 4bd
8a+2b