It can't be factored because its discriminant is less than zero
It can be. x^2 + x + 1 is a factor of 2x^2 + 2x + 2
(x + 2)(x - 1)
x2 + x - 6 = (x + 3)(x - 2)
x2 + 26x + 48 = (x + 24)(x + 2)
x2 + 6x + 8 = (x + 4)(x + 2)
(x - 1)(x - 2)
x2 + 8x + 12 = (x + 6) (x + 2)
(x + 6)(x + 2)
(x + 10)(x + 2)
Factor x3 + x2 + 2x + 2, by grouping. Group the first two terms and the last two terms. Then factor. First, factor x3 + x2 by pulling out an x2 term: x2(x + 1) Second, factor 2x + 2 by pulling out a 2: 2(x + 1) So, you now have: x2(x + 1) + 2(x + 1) If you have factored correctly, the terms inside the parentheses should be the same. Now regroup. ANS: (x + 1)(x2 + 2)
x2 + 10 - 24 = (x + 12)(x - 2)
(x+7)(x+2)