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Q: How do you factor x2 plus 8x plus 15?

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x2 + 8x + 15 = (x + 3)(x + 5)

x2-8x+15 = (x-3)(x-5)

That does not factor neatly.

8x(x2-x+1)

x2 + 8x = x(x+8)

x2-8x+16 = (x-4)(x-4) when factored

x² + 8x + 15 = (x + 5)(x + 3)

(-4,-1)

x2 + 8x = -15 x2 + 8x + 15 = 0 since 15 = 5 x 3 and 5 + 3 = 8, then (x + 5)(x + 3) = 0 x + 5 = 0 or x + 3 = 0 x = -5 or x = -3

(x + 6)(x + 2)

x2 + 8x + 12 = (x + 6) (x + 2)

(x+1)(x+7)

2x(x2+2x+4)

No because the discriminant is less than zero.

x + 4

(x+5)(x+3)

(x-4)(x-4)

3(x2-x-7)

X2 - 8X + 15 = (X - 3)(X - 5)

(x - 3)(x - 5)

(x - 4)(x - 4)

y = x2 + 8x + 15 = (x + 3)(x + 5). When y = 0, one or other of the two factors must equal zero; that is, x = -3 or -5, when y = 0.

x2-8x+12 = (x-2)(x-6) when factored

x2 - 8x + 32 = 0 (assuming)you can factor or use the quadratic equation.I recommend the quadratic equation.

(x - 2)(x - 2)(x2 + 2x + 4)