x2 + 2x - 12
Since factors of -12 cannot add up to 2, then I will complete the square in order to factor it as a difference of the two squares.
x2 + 2x - 12 add and subtract 1
= (x2 + 2x + 1) - 1 - 12
= (x + 1)2 - 13 represent 13 as (√13)2
= (x + 1)2 - (√13)2
= [(x + 1) - √13][(x + 1) + √13]
(a - 2)(a^2 + 6)
There are no rational factors.
There is no rational factorisation.
(b-c)(a+b)-ac
(x + 3)(3x - 2)
(3y - 5)(y + 5)
(7a - 1)(6a + 1)
(3r - 2)(3r - 2) or (3r - 2) squared.
it is (x-y)(x-y) :)
6(b - ac + b2 - bc)
6(ab - ac + b2 - bc)
Factor out -2: -2(x squared +11x-20). This is fully factored.