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Q: How do you factorise 4x2 plus 16?

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(4x-3)(x+2)

It can't be factored because the discriminant is less than zero.

4x2 + 12x + 5 = 4x2 + 2x + 10x + 5 = 2x(2x+1) + 5(2x+1) = (2x+1)(2x+5)

16

First you need to solve for y. So write 4x2+y=16 so y=16-4x2 Now write f(x)=16-4x2

It is; (2x+4)^2.

(4x + 16)(x + 3)

4(x + 2)(x + 2)

4x2 - 6x - 12 = 2 (2x2 - 3x - 6) There are no integer roots, the approximate roots are 2.64 and -1.14

4x2+8x+3 ------> (2x+3)(2x+1)

(y - 8)(y - 2)

a2+16 cannot be factored. There are no two numbers whose product is 16 and whose sum is 0.

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