8x3 + 4x2 + 6x + 3 = 4x2(2x + 1) + 3(2x + 1) = (2x + 1)(4x2 + 3)
If you mean: 6x^2 +7x-3 then it is (2x+3)(3x-1) when factored
4x2 + 6x - 3 (with no remainder)
4x2 plus 3=11
x*2 - 6x + 9 x*2 -3x -3x +9 x(x-3) -3(x-3) (x-3)(x-3) Note also that x*2 - 6x + 9 is of the form a*2 -2ab + b*2 and so the factors are (x-3) and (x-3)
8x3 + 4x2 + 6x + 3 = 4x2(2x + 1) + 3(2x + 1) = (2x + 1)(4x2 + 3)
This is how I did it:8x3+4x2+6x+3[8x3+4x2]+[6x+3][(4x2)(2x+1)]+[(3)(2x+1)]....as you can see, this is in the general form of ab+cb, which factored is b(a+c), so:(2x+1)(4x2+3)
(4x-3)(x+2)
If you mean: 6x^2 +7x-3 then it is (2x+3)(3x-1) when factored
6x^3 + 3x = 3x(2x^2 + 1)
4x2 - 12x + 9 = 4x2 - 6x - 6x + 9 = 2x(2x - 3) - 3(2x - 3) = (2x - 3)(2x - 3) or (2x - 3)2
2x(y - 3) + 7(y - 3) = (2x + 7)(y - 3)
6x + 9x^3 = 3x*(2 + 3x^2)
(6x^5-4x^2)+(2x^3-3) = 6x^5-4x^2+2x^3-3 The grestest exponent is 5, which is the degree of the above expression.
4x2+8x+3 ------> (2x+3)(2x+1)
4x2 + 6x - 3 (with no remainder)
5x^2 + 6x - 2 doesn't factor neatly. Applying the quadratic formula, we find two real solutions: (-3 plus or minus the square root of 19) divided by 5. x = 0.2717797887081348 x = -1.4717797887081348