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6ab2 + 7a2b

find the common variables and numbers:

In this case only the variables are common and they are a & b. so you take out a &b out of the brackets and factorise.

Answer: ab(6b+7a)

Q: How do you factorise 6ab2 plus 7a2 b?

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It is: 5(3a+b) when factored

2a2b2+3a2b2-5abc

To evaluate it you need to know both b and a. But it is possible to factorise it as follows: b2-a2 = (b-a)*(b+a)

0

For a polynomial a2 - b2 = (a + b)(a - b).So for x2 - 16y2 ---> a = x, and b = 4y: (x + 4y)(x - 4y)

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It is: 5(3a+b) when factored

2 x 3 x A x b x b = 6Ab2

2a2b2+3a2b2-5abc

15

-9(a + b)

To evaluate it you need to know both b and a. But it is possible to factorise it as follows: b2-a2 = (b-a)*(b+a)

It is possible to factorise 4x²-9 further.Factorising is to express a number or expression as a product of factors.The technique of factorising two terms: a² - b² = (a + b) (a - b)If we apply ( 4x²-9 ) to the previous technique: 4x² - 9 = (2x + 3) (2x - 3)

0

2a + 4b + 8c = 2(a + 2b + 4c) You could also continue by factoring the inside of the parentheses a bit: 2a + 4b + 8c = 2(a + 2b + 4c) = 2(a + 2[b + 2c])

Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "times", "equals", "squared", "cubed". It is not clear what the 2, at the end of the expression is meant to indiacte.

14

For a polynomial a2 - b2 = (a + b)(a - b).So for x2 - 16y2 ---> a = x, and b = 4y: (x + 4y)(x - 4y)