6ab2 + 7a2b
find the common variables and numbers:
In this case only the variables are common and they are a & b. so you take out a &b out of the brackets and factorise.
Answer: ab(6b+7a)
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It is: 5(3a+b) when factored
2a2b2+3a2b2-5abc
To evaluate it you need to know both b and a. But it is possible to factorise it as follows: b2-a2 = (b-a)*(b+a)
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For a polynomial a2 - b2 = (a + b)(a - b).So for x2 - 16y2 ---> a = x, and b = 4y: (x + 4y)(x - 4y)