I am thinking you must mean x^2-4x+3 otherwise it would be x^2-1 which would factor as (x+1)(x-1).
In any case, it factors as (x-3)(x-1). Just look at the last number, 3 and note it has factors 3 and 1. Now need those factors to add up to -4 and their product to be positive. We must pick -1 and -3.
It is: 3(t+3)
It is: 6(4x+3)
It is 3a(a+3) when factored
It is: 3(x+2)
(2n+3)(n+1)=2n2+5n+3.
(x+5)(x+3)
Answer this question…A. x4 + 2x3 + 9x2 + 4 B. x4 + 4x3 + 9x2 + 4 C. x4 + 2x3 + 9x2 + 4x + 4 D. x4 + 2x3 + 9x2 - 4x + 4
It is 3(2y+5) when factorised
(5x + 2)(x + 3)
(4x-3)(x+2)
(x-7)(x-3)
It is 2(2x+3) when factorised