It is (x-3)(x-4) when factored
x2+bx+ax+ab = x2+ax+bx+ab = x(x+a)+b(x+a) = (x+a)(x+b)
x2+x x(x+1)
It cannot be factored because the discriminant is less than zero. Do you mean x2+11x-60 then if so it is (x-4)(x+15)
4x2 + x2 = 8 + x2
X = 8 x2 (8)2 = 64 ====
x2+7x-8 = (x-1(x+8)
x2 + 7x - 8 = (x + 8)(x - 1)
x2+7x-8 = (x-1(x+8)
If x = 8 then x2 = 82 = 8 x 8 = 64
If you mean: 32w+8 then it can be factored to 8(4w+1)
x2 - 9x = -8 ∴ x2 - 9x + 8 = 0 ∴ (x - 1)(x - 8) = 0 You can then solve it as well: ∴ x ∈ {1, 8}