Easier to show you a simple example as I forget the formulaic approach.
X2 + 4X - 6 = 0
add 6 to each side
x2 + 4X = 6
Now, halve the linear term ( 4 ), square it and add it to both sides
X2 + 4X + 4 = 6 + 4
gather the terms on the right side and factor the left side
(X + 2)2 = 10
subtract 10 from each side
(X + 2)2 - 10 = 0
(- 2, - 10 )
-------------------the vertex of this quadratic function
2 AND 9
Yes, the coordinates for the vertex of a quadratic function in the form (y = ax^2 + bx + c) can be found using the formula (x = -\frac{b}{2a}) to determine the x-coordinate. Once you have the x-coordinate, substitute it back into the original equation to find the corresponding y-coordinate. This gives you the vertex in the form ((x, y)).
The highest or lowest point on the graph of a quadratic function, known as the vertex, depends on the direction of the parabola. If the parabola opens upwards (the coefficient of the (x^2) term is positive), the vertex represents the lowest point. Conversely, if the parabola opens downwards (the coefficient is negative), the vertex is the highest point. The vertex can be found using the formula (x = -\frac{b}{2a}) to find the (x)-coordinate, where (a) and (b) are the coefficients from the quadratic equation (ax^2 + bx + c).
To determine the quadratic function from a graph, first identify the shape of the parabola, which can open upwards or downwards. Look for key features such as the vertex, x-intercepts (roots), and y-intercept. The standard form of a quadratic function is ( f(x) = ax^2 + bx + c ), where ( a ) indicates the direction of the opening. By using the vertex and intercepts, you can derive the coefficients to write the specific equation of the quadratic function.
The vertex of the quadratic function ( f(x) = ax^2 + bx + c ) can be found using the formula ( x = -\frac{b}{2a} ). Once you determine the x-coordinate of the vertex, you can substitute it back into the function to find the corresponding y-coordinate. Therefore, the vertex is at the point ( \left(-\frac{b}{2a}, f\left(-\frac{b}{2a}\right)\right) ). If the function is given as ( f(x) = x^2 + c ) (where ( a = 1 ) and ( b = 0 )), the vertex simplifies to ( (0, c) ).
it is a vertices's form of a function known as Quadratic
It if the max or minimum value.
vertex
2 AND 9
The graph of a quadratic function is always a parabola. If you put the equation (or function) into vertex form, you can read off the coordinates of the vertex, and you know the shape and orientation (up/down) of the parabola.
It is a turning point. It lies on the axis of symmetry.
The minimum is the vertex which in this case is 0,0 or the origin. There isn't a maximum.....
vertex
The vertex must be half way between the two x intercepts
The standard form of the quadratic function in (x - b)2 + c, has a vertex of (b, c). Thus, b is the units shifted to the right of the y-axis, and c is the units shifted above the x-axis.
The vertex.
The zeros of a quadratic function, if they exist, are the values of the variable at which the graph crosses the horizontal axis.