Easier to show you a simple example as I forget the formulaic approach.
X2 + 4X - 6 = 0
add 6 to each side
x2 + 4X = 6
Now, halve the linear term ( 4 ), square it and add it to both sides
X2 + 4X + 4 = 6 + 4
gather the terms on the right side and factor the left side
(X + 2)2 = 10
subtract 10 from each side
(X + 2)2 - 10 = 0
(- 2, - 10 )
-------------------the vertex of this quadratic function
2 AND 9
Do you have a specific vertex fraction? vertex = -b/2a wuadratic = ax^ + bx + c
A quadratic function will have a degree of two.
A quadratic function is a second degree polynomial, that is, is involves something raised to the power of 2, also know as squaring. Quadratus is Latin for square. Hence Quadratic.
It is (1, 1).
it is a vertices's form of a function known as Quadratic
It if the max or minimum value.
vertex
2 AND 9
The graph of a quadratic function is always a parabola. If you put the equation (or function) into vertex form, you can read off the coordinates of the vertex, and you know the shape and orientation (up/down) of the parabola.
It is a turning point. It lies on the axis of symmetry.
The minimum is the vertex which in this case is 0,0 or the origin. There isn't a maximum.....
vertex
The vertex must be half way between the two x intercepts
The standard form of the quadratic function in (x - b)2 + c, has a vertex of (b, c). Thus, b is the units shifted to the right of the y-axis, and c is the units shifted above the x-axis.
The zeros of a quadratic function, if they exist, are the values of the variable at which the graph crosses the horizontal axis.
The vertex.