to calculate the area of any straight line graph or part of a graph, you need to select two points.
for example (x1,y1) and (x2,y2).
once you have selected the points you put then into the equation
m=delta y/delta x (change in y divided by the change in x)
which is easier as
m=(y2-y1)/(x2-x1)
and m = the gradient
It is the gradient (slope) of the line.
Simply put, a velocity time graph is velocity (m/s) in the Y coordinate and time (s) in the X and a position time graph is distance (m) in the Y coordinate and time (s) in the X if you where to find the slope of a tangent on a distance time graph, it would give you the velocity whereas the slope on a velocity time graph would give you the acceleration.
A velocity time graph is still a velocity time graph - no matter the degree of detail that you look at it.
The gradient of the graph.
The gradient (slope) of the tangent to the graph at the given time - provided that it exists. If the graph is a straight line at that point, it is the gradient of that line.
It is the downward gradient of the graph.
It is the gradient (slope) of the line.
You can't, since the slope of the graph means average velocity and the area of the graph has no meaning. The only way to find instantaneous velocity from position-time gragh is by plugging the data into the kinematic equations to get the answer. Edit: Actually you can if you take the derivative of the equation of the curve it will give you the equation of the velocity curve
deceleration can be measured from a velocity time graph by calculating the gradient of the velocity time graph if the V-t graph was linear. If the v-t graph was a curve then the differentiatial of the equation of the curve will give the deceleration variation with time.
You can't. However, you can find the change in speed between two points in time by finding the area under the acceleration-time graph.
Simply put, a velocity time graph is velocity (m/s) in the Y coordinate and time (s) in the X and a position time graph is distance (m) in the Y coordinate and time (s) in the X if you where to find the slope of a tangent on a distance time graph, it would give you the velocity whereas the slope on a velocity time graph would give you the acceleration.
A velocity time graph is still a velocity time graph - no matter the degree of detail that you look at it.
A distance-time graph for an object moving at a constant velocity will be a straight line - the gradient of the line corresponds to the velocity. Non-uniform motion will cause the gradient of the line to change.
you can't....it's merely impossible! Assuming it is a graph of velocity vs time, it's not impossible, it's simple. Average velocity is total distance divided by total time. The total time is the difference between finish and start times, and the distance is the area under the graph between the graph and the time axis.
this time is basically the instant when an object has a particular velocity(instantaneous velocity). so on the graph draw a line from the particular value of the velocity and then draw a vertical line on time axis to find the time for that velocity.
take the slope of every change in the velocity time graph and plot it
The gradient of a distance-time graph gives the object's speed.