-- The perimeter is (2 lengths) plus (2 widths).
-- You know the width, so you can subtract it from the perimeter twice.
-- When you do that, the number you have left will be (2 lengths).
-- Surely you can handle it from here.
==========================================================
Whichever way you choose to solve this problem,
you must also carry out this final step:
-- If your solution is not ' 7 ', then go back to Step-1, rinse, and repeat.
It is impossible to find the perimeter without the width of the rectangle but if you want a formula it would be (43*2) + 2x. x representing the width
Add the length and the width; Double the answer; Job done.
Half perimeter = 109. Subtract 87 and half the answer 22/2 = 11, this is the width. Add on the 87 giving 98, this is the length.
you need length and width length multiply width = area length + length + width + width = perimeter
That would be 3 x 9 inches.
The perimeter of a rectangle = 2 x (length + width) = 2 x (12 + 8) = 2 x 20 = 40 inches
Length of rectangle is 5 inches and its width is 4 inches Check: 2*(5+4) = 18 inches which is its perimeter
The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.
the length of a rectangle is 5 more then the width. Find the perimeter and the area of the rectangle
Width = 9 inches Length = 30 inches
Do-it-in-your-head method: Length + width is half the perimeter which is 27 inches; 27 minus 6 is 21 and one-third of 21 is 7 which is the width. (Length = 2 x 7 + 6 = 20)
It is impossible to find the perimeter without the width of the rectangle but if you want a formula it would be (43*2) + 2x. x representing the width
Add the length and the width; Double the answer; Job done.
Half perimeter = 109. Subtract 87 and half the answer 22/2 = 11, this is the width. Add on the 87 giving 98, this is the length.
If the rectangle has a width of x inches, and a length of x + 16 inches, then its perimeter equals to 2x + 2x + 32 or 4x + 32. If x = 14, then x + 16 = 30. So the perimeter of rectangle becomes 2(14) + 2(30) = 28 + 60 = 88 inches.
you need length and width length multiply width = area length + length + width + width = perimeter
If the length of a rectangle is twice its width and it has a perimeter of 48, then the rectangle is 16 in length and 8 in width.