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Suppose P = (x, y) are the coordinates of any point on the line.

Then the segment of the line joining P to the point (3, 2k) has slope k

That is,

(y - 2k) / (x - 3) = k

Simplifying, y - 2k = kx - 3k

or y = kx - k

equivalently, y = k(x - 1)

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Q: How do you find the straight line equation given only that the slope is k passing through a point 3 and 2k on the line?
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