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From the information given it appears to have no slope if x0 and so there is no equation as such but plotted on a grid there will be a straight vertical line and a straight horizontal line that meet each other at right angles.

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Q: What is the slope-intercept equation of a line that goes through (54) and is perpendicular to x0 (Algebra 1) Can you walk me through it step by step?
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What is perpendicular to the line 3x plus y equals 2?

If a line has equation y = mx + c, the perpendicular line has gradient -1/m A line perpendicular to 3x + y = 2 has equation 3y = x + c; the value for c will be determined by a point through which the line must pass.


Write the equation of the line through (2 3) that is perpendicular to y -2x - 2.?

If you mean: y = -2x -2 and point of (2, 3)Then perpendicular equation is: y-3 =1/2(x-2) => 2y = x+4


What equation represents a line perpendicular to y equals x and passing through the points 0 0?

y=-x


What is the equation that passes through the point 3 and -1 and is perpendicular to the line 2x-4y equals 8?

Slope: -2 Equation: y--1 = -2(x-3) => y = -2x+5


How do I write the equation of the line that passes through the given point and is perpendicular to the given line Write the answer in slope-intercept form?

The standard equation for a straight line is y = mx + c. Let this be the equation of the original line. Note that m and c are known values. Let the given point coordinates be (a,b)Two straight lines are perpendicular if the product of their gradients (slopes) is -1.The slope (m1) of the perpendicular line is therefore m1 = -1/mWhen y = b then x = a so the equation for the perpendicular line is y = m1x + d, and substituting gives : b = -a/m + d and this will enable d to be calculated.NOTE : In the absence of information for the equation of the original line and the coordinates of the given point then this is a general rather than a specific answer.

Related questions

What is the equation of the line that it is perpendicular to y7x-3 and passes through the origin?

If you mean 7 = 7x-3 then the perpendicular slope is -1/7 and the equation is y = -1/7x


What is the equation of a line that passes through the point 0 -3 and is perpendicular to a line with a slope of 4?

Perpendicular slope: -1/4 Perpendicular equation: y-0 = -1/4(x-3) => y = -0.25x+3


What is the equation of a line that is perpendicular to and passes through the point (8 3)?

That depends on the equation that it is perpendicular too which has not been given but both equations will meet each other at right angles.


What is the equation of the line passing through 3 -4 and it is perpendicular to the line 5x -2y equals 3?

Known equation: 5x -2y = 3 or y = 5/2x -3/2 Slope of equation: 5/2 Slope of perpendicular equation: -2/5 Perpendicular equation: y --4 = -2/5(x -3) => 5y = -2x -14 Perpendicular equation in its general form: 2x+5y+14 = 0


Generally how do you fit a function to an EDF and CDF and is there a generic equation?

You can fit a function to an EDF and CDF through algebra. There is no generic equation.


What is the equation of a line that passes through 3 -4 and is perpendicular to 5x -2y equals 3 on the Cartesian plane?

Perpendicular slope: -2/5 Perpendicular equation: y--4 = -2/5(x-3) => 5y--20 = -2x-3 => 5y = -2x-14 Perpendicular equation in its general form: 2x+5y+14 = 0


What is the equation of the line passing through -2 -3 that is at right angles to the equation 4x plus 3y -5 equals 0 on the Cartesian plane?

The equation will be perpendicular to the given equation and have a slope of 3/4:- Perpendicular equation: y--3 = 3/4(x--2) => 4y--12 = 3x--6 => 4y = 3x-6 Perpendicular equation in its general form: 3x-4y-6 = 0


What is the equation passing through the point 3 -4 which is perpendicular to the line 5x -2y equals 3?

Known equation: 5x-2y = 3 or y = 5/2x -3/2 Slope of known equation: 5/2 Slope of perpendicular equation: -2/5 Perpendicular equation: y- -4 = -2/5(x-3) => 5y =-2x-14 Perpendicular equation in its general form: 2x+5y+14 = 0


What is the equation of the line that is perpendicular to -x y 7 and passes through -1 -1?

Without an equality sign and not knowing the plus or minus values of y and 7 it can't be considered to be a straight line equation therefore finding its perpendicular equation is impossible.


What equation describes a line that passes through the point (-14) and is perpendicular to the line 4x-3y-9?

If you mean point (-1, 4) and equation of 4x-3y = -9 then y = 4/3x+3 Slope of equation: 4/3 Perpendicular slope: -3/4 Perpendicular equation: y-4 = -3/4(x--1) => 4y = -3x+13


How do you Write the equation of the line that is perpendicular to y 3x plus 8 and passes through the point (-3 4).?

If you mean y = 3x+8 then the perpendicular slope will be -1/3 and the equation works out as 3y = -x+9


What is the equation of a line that passes through the point 2 5 and is perpendicular to a line with a slope of -2?

Perpendicular slope: 1/2 Perpnedicular equation: y-5 = 1/2(x-2) => y = 0.5x+4