0
sin2(x) + 2 sin(x) + 1
It might be easier for you if you use 'S' temporarily to represent 'sin(x)', just long enough to look at it.
Then you have
S2 + 2S + 1
Can you 'foil' that ?
It's just the square of (S + 1). The factors are (S+1) and (S+1).
The original expression is the square of [sin(x) + 1].
What else can I help you with?
What is a numerical value for x if cos2x plus 2sinx-2 equals 0?
cos2x + 2sinx - 2 = 0 (1-2sin2x)+2sinx-2=0 -(2sin2x-2sinx+1)=0 -2sinx(sinx+1)=0 -2sinx=0 , sinx+1=0 sinx=0 , sinx=1 x= 0(pi) , pi/2 , pi
How do you solve 2Sinx 1 equals 0?
2sinx+1 equals 0
What is 1-sin2?
1-sin2 = -1
What is the solution to cos2 plus cos2tan2 equals 1?
cos2 + cos2tan2 = cos2 + cos2*sin2/cos2 = cos2 + sin2 which is identically equal to 1. So the solution is all angles.
Solve 2sinx-sin3x equals 0?
2sinx - sin3x = 0 2sinx - 3sinx + 4sin3x = 0 4sin3x - sinx = 0 sinx(4sin2x - 1) = 0 sinx*(2sinx - 1)(2sinx + 1) = 0 so sinx = 0 or sinx = -1/2 or sinx = 1/2 It is not possible to go any further since the domain for x is not defined.
By using trigonometry identities find the value of a sin A if TAN A equals half?
tan(A) = 1/2 sin(A)/cos(A) = 1/2 sin2(A)/cos2(A) = 1/4 sin2(A)/[1 - sin2(A)] = 1/4 sin2(A) = 1/4*[1 - sin2(A)] 5/4*sin2(A) = 1/4 sin2(A) = 1/5 sin(A) = ±sqrt(1/5) = ±sqrt(5)/5
What does negative sine squared plus cosine squared equal?
To determine what negative sine squared plus cosine squared is equal to, start with the primary trigonometric identity, which is based on the pythagorean theorem...sin2(theta) + cos2(theta) = 1... and then solve for the question...cos2(theta) = 1 - sin2(theta)2 cos2(theta) = 1 - sin2(theta) + cos2(theta)2 cos2(theta) - 1 = - sin2(theta) + cos2(theta)
Sine plus cosine equals?
There is no real significance to sine plus cosine, now sin2(x) + cos2(x) = 1 for any x, where sin2(x) means to take the sign of the number, then square that value.
How does 1-sin squared x times 1 plus tan suared x equals 1?
Use these identities: sin2(x) + cos2(x) = 1, and tan(x) = sin(x)/cos(x) For clarity, the functions are written here without their arguments (the "of x" part). (1 - sin2) = cos2 (1 + tan2) = (1 + sin2/cos2) = (cos2+sin2) / cos2 = 1/cos2 Multiply them: (cos2) times (1/cos2) = 1'QED'
Can you show 1 divided by 1 plus cosx equals cscsquaredx minus cscxcotx?
2
What is sin squared minus 1?
-cos2(x)1 = sin2(x) +cos2(x)1 - cos2(x) = sin2(x)-cos2(x) = sin2(x) - 1
If sinX plus cosecx equals 2 find sin40x plus cosec50x?
sin x + csc x = 2 sin x + 1/sin x = 2 (sin2 x + 1)/sin x = 2/1 (cross multiply) sin2 x + 1 = 2sin x (subtract 2sin x to both sides) sin2 x - 2sinx + 1 = 0 (sin x - 1)2 = 0 (take the square root of both sides) sin x - 1 = 0 (add 1 to both sides) sin x = 1 x = sin-1 1 = 90⁰ 40x = 40(90⁰) = 3,600⁰ sin 40x = sin (3,600⁰ ) = 0 50x = 50(90⁰) = 4500⁰ sin 50x = sin (4,500⁰) = 0, so that csc 50x is undefined, we cannot divide by 0. Then, sin40x + csc50x is undefined.
