[ y = 3x ] has no asymptote. Its range and domain are both infinite. Its graph is a
straight line, with a slope of 3, that enters from the bottom left, passes through the
origin, and exits at the top right. No matter how wide or high you make your
coordinate space, the graph still does that. You'll never find its end.
[ y = log(x) ] exists only in the right half of the plane, where 'x' is positive, so the
domain is from x=0 to infinite. Within that domain, 'y' ranges from negative infinite
to positive infinite.
The graph crosses the x-axis at [x=1].
To the left of that point, it plunges through all negative values, from zero to negative
infinite. The y-axis is the asymptote. That part of the graph looks like an inverted
hockey stick, with an infinite handle and a tiny tiny blade.
To the right of that point, where 'x' is greater than '1', the graph rises at a
slowly-increasing rate. It obviously curves upward, and one might think that
if we looked far enough out to the right, there might be another vertical
asymptote somewhere way out there in the land of great x-values. But
there isn't, and there are no x-values that it can't reach. The graph looks like
a right-side-up hockey stick with a monstrous blade and a timid handle.
The domain is (-infinity, infinity) The range is (-3, infinity) and the asymptote is y = -3
asymptote
x-axis
no
2x-2/x^2+3x-4
The domain is (-infinity, infinity) The range is (-3, infinity) and the asymptote is y = -3
asymptote
The domain of the function f(x) = (x + 2)^-1 is whatever you choose it to be, except that the point x = -2 must be excluded. If the domain comes up to, or straddles the point x = -2 then that is the equation of the vertical asymptote. However, if you choose to define the domain as x > 0 (in R), then there is no vertical asymptote.
y = 4(2x) is an exponential function. Domain: (-∞, ∞) Range: (0, ∞) Horizontal asymptote: x-axis or y = 0 The graph cuts the y-axis at (0, 4)
x-axis
x axis
no
- 2 makes this zero and provides the vertical asymptote. So, from - infinity to - 2 and from - 2 to positive infinity
2x-2/x^2+3x-4
Yes, the asymptote is x = 0. In order for logarithmic equation to have an asymptote, the value inside log must be 0. Then, 5x = 0 → x = 0.
Yes. Take the functions f(x) = log(x) or g(x) = ln(x) In both cases, there is a vertical asymptote where x = 0. Because a number cannot be taken to any power so that it equals zero, and can only come closer and closer to zero without actually reaching it, there is an asymptote where it would equal zero. Note that transformations (especially shifting the function left and right) can change the properties of this asymptote.
The horizontal asymptote for y = 0 when the degree is greater than the denominator, resulting in the inability to do long division.