Use two of the 3s to make 33.
Then:
33 - 3 = 11
11 + 3 = 14
3 * 3 / ( 3 * 3 ) = 1 but that uses only four 3s, so 33 / ( 3 * 3 * 3 ) = 1 uses five 3s
33 + (3/3)
33 x 33/3 = 33 x 11 = 363
28 3s
L + S = 72 so L = 72 - S; 4L - 3S = 78 ie 4(72 - S) - 3S = 78 ie 288 - 4S - 3S = 78 ie 7S = 210 so S = 30 and L = 42. And there you have it!
3 * 3 / ( 3 * 3 ) = 1 but that uses only four 3s, so 33 / ( 3 * 3 * 3 ) = 1 uses five 3s
4=4(3s) 4=12s s= 1/3
You can't unless something is missing in your question.
3x7+4x2
33/3 = 11
(3 + 3) / .3
Is done by (3/3) plus (3/3) = 2
It could be done by: (3*3)/(3*3) = 1
(3*3+3)/3=4
It could be: 33-(3+3) = 21
3/3 + 3/3 = 6/3 = 2
33 + (3/3)