Use two of the 3s to make 33.
Then:
33 - 3 = 11
11 + 3 = 14
3 * 3 / ( 3 * 3 ) = 1 but that uses only four 3s, so 33 / ( 3 * 3 * 3 ) = 1 uses five 3s
33 + (3/3)
33 x 33/3 = 33 x 11 = 363
28 3s
L + S = 72 so L = 72 - S; 4L - 3S = 78 ie 4(72 - S) - 3S = 78 ie 288 - 4S - 3S = 78 ie 7S = 210 so S = 30 and L = 42. And there you have it!
4=4(3s) 4=12s s= 1/3
3 * 3 / ( 3 * 3 ) = 1 but that uses only four 3s, so 33 / ( 3 * 3 * 3 ) = 1 uses five 3s
You can't unless something is missing in your question.
3x7+4x2
33/3 = 11
(3 + 3) / .3
Is done by (3/3) plus (3/3) = 2
You can create numbers 10-20 using four 3s through various mathematical operations. For example, to make 10, you can use the expression (3 \times 3 + 3 - 3). To create 12, you can use (3 \times 3 + 3). Similarly, for 15, you can use (3 \times 3 + 3 + 3), and for 18, the expression (3 \times 3 + 3 + 3 + 3) works as well.
(3*3+3)/3=4
It could be done by: (3*3)/(3*3) = 1
The electron orbitals of silicon are 1s, 2s, 2p, 3s, and 3p. Silicon has a total of 14 electrons, with two electrons in the 1s orbital, eight electrons in the 2s and 2p orbitals, and four electrons in the 3s and 3p orbitals.
It could be: 33-(3+3) = 21