3 * 3 / ( 3 * 3 ) = 1 but that uses only four 3s, so 33 / ( 3 * 3 * 3 ) = 1 uses five 3s
33 + (3/3)
33 x 33/3 = 33 x 11 = 363
28 3s
L + S = 72 so L = 72 - S; 4L - 3S = 78 ie 4(72 - S) - 3S = 78 ie 288 - 4S - 3S = 78 ie 7S = 210 so S = 30 and L = 42. And there you have it!
3 * 3 / ( 3 * 3 ) = 1 but that uses only four 3s, so 33 / ( 3 * 3 * 3 ) = 1 uses five 3s
4=4(3s) 4=12s s= 1/3
You can't unless something is missing in your question.
3x7+4x2
33/3 = 11
(3 + 3) / .3
Is done by (3/3) plus (3/3) = 2
It could be done by: (3*3)/(3*3) = 1
(3*3+3)/3=4
The electron orbitals of silicon are 1s, 2s, 2p, 3s, and 3p. Silicon has a total of 14 electrons, with two electrons in the 1s orbital, eight electrons in the 2s and 2p orbitals, and four electrons in the 3s and 3p orbitals.
PH4 has sp3 hybridization. This means that the phosphorus atom forms four sigma bonds using one 3s orbital and three 3p orbitals.
It could be: 33-(3+3) = 21