Use two of the 3s to make 33.
Then:
33 - 3 = 11
11 + 3 = 14
3 * 3 / ( 3 * 3 ) = 1 but that uses only four 3s, so 33 / ( 3 * 3 * 3 ) = 1 uses five 3s
33 + (3/3)
33 x 33/3 = 33 x 11 = 363
28 3s
L + S = 72 so L = 72 - S; 4L - 3S = 78 ie 4(72 - S) - 3S = 78 ie 288 - 4S - 3S = 78 ie 7S = 210 so S = 30 and L = 42. And there you have it!
4=4(3s) 4=12s s= 1/3
3 * 3 / ( 3 * 3 ) = 1 but that uses only four 3s, so 33 / ( 3 * 3 * 3 ) = 1 uses five 3s
You can't unless something is missing in your question.
You can make 1 using three 3s by performing the following calculation: (3 + 3) / 3. Here, you add two 3s to get 6, and then divide by the third 3 to achieve the result of 1.
3x7+4x2
33/3 = 11
(3 + 3) / .3
Is done by (3/3) plus (3/3) = 2
You can create numbers 10-20 using four 3s through various mathematical operations. For example, to make 10, you can use the expression (3 \times 3 + 3 - 3). To create 12, you can use (3 \times 3 + 3). Similarly, for 15, you can use (3 \times 3 + 3 + 3), and for 18, the expression (3 \times 3 + 3 + 3 + 3) works as well.
(3*3+3)/3=4
It could be done by: (3*3)/(3*3) = 1
The electron orbitals of silicon are 1s, 2s, 2p, 3s, and 3p. Silicon has a total of 14 electrons, with two electrons in the 1s orbital, eight electrons in the 2s and 2p orbitals, and four electrons in the 3s and 3p orbitals.