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How do you simplify csc theta -cot theta cos theta?
For a start, try converting everything to sines and cosines.
What is cos theta?
The side adjacent to theta divided by the hypotenuse, or the angle opposite of the right angle
How do you simplify csc theta minus cot x theta times cos theta plus 1?
There can be no significant simplicfication if some of the angles are theta and others are x, so assume that all angles are x. [csc(x) - cot(x)]*[cos(x) + 1] =[1/sin(x) - cos(x)/sin(x)]*[cos(x) + 1] =1/sin(x)*[1 - cos(x)]*[cos(x) + 1] =1/sin(x)*[1 - cos2(x)] =1/sin(x)*[sin2(x)] = sin(x)
Force times distance is?
A - WORKWork = F.s cos (theta)
What is the identity for tan theta?
The identity for tan(theta) is sin(theta)/cos(theta).
How do you simplify tan theta cos theta?
Remember that tan = sin/cos. So your expression is sin/cos times cos. That's sin(theta).
What is cos theta times cos theta?
Cos theta squared
How do you simplify csc theta -cot theta cos theta?
For a start, try converting everything to sines and cosines.
How do you simplify csc theta cot theta cos theta?
cosec(q)*cot(q)*cos(q) = 1/sin(q)*cot(q)*cos(q) = cot2(q)
What is cos theta?
The side adjacent to theta divided by the hypotenuse, or the angle opposite of the right angle
What is sec squared theta times cos squared theta minus tan squared theta?
Tan^2
How do you simplify csc theta minus cot x theta times cos theta plus 1?
There can be no significant simplicfication if some of the angles are theta and others are x, so assume that all angles are x. [csc(x) - cot(x)]*[cos(x) + 1] =[1/sin(x) - cos(x)/sin(x)]*[cos(x) + 1] =1/sin(x)*[1 - cos(x)]*[cos(x) + 1] =1/sin(x)*[1 - cos2(x)] =1/sin(x)*[sin2(x)] = sin(x)
What is cos theta minus cos theta times sin squared theta?
cos(t) - cos(t)*sin2(t) = cos(t)*[1 - sin2(t)] But [1 - sin2(t)] = cos2(t) So, the expression = cos(t)*cos2(t) = cos3(t)
How do you solve theta if cos squared theta equals 1 and 0 is less than or equal to theta which is less than 2pi?
cos2(theta) = 1 so cos(theta) = ±1 cos(theta) = -1 => theta = pi cos(theta) = 1 => theta = 0
How do you simplify cot of theta times sin of theta?
By converting everything to sines and cosines. Since tan x = sin x / cos x, in the cotangent, which is the reciprocal of the tangent: cot x = cos x / sin x. You can replace any other variable (like thetha) for the angle.
Force times distance is?
A - WORKWork = F.s cos (theta)
De Morgan's law in complex number?
(Sin theta + cos theta)^n= sin n theta + cos n theta
