Best Answer

'csc' = 1/sin

'tan' = sin/cos

So it must follow that

(cos) (csc) / (tan) = (cos) (1/sin)/(sin/cos) = (cos) (1/sin) (cos/sin) = (cos/sin)2

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โˆ™ 2012-02-28 20:58:02
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Q: How do you simplify cos theta times csc theta divided by tan theta?
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Related questions

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Remember that tan = sin/cos. So your expression is sin/cos times cos. That's sin(theta).

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For a start, try converting everything to sines and cosines.

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What is sec squared theta times cos squared theta minus tan squared theta?


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What is cos theta minus cos theta times sin squared theta?

cos(t) - cos(t)*sin2(t) = cos(t)*[1 - sin2(t)] But [1 - sin2(t)] = cos2(t) So, the expression = cos(t)*cos2(t) = cos3(t)

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De Morgan's law in complex number?

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Should we find cos theta if sec theta equals -10?


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