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'csc' = 1/sin

'tan' = sin/cos

So it must follow that

(cos) (csc) / (tan) = (cos) (1/sin)/(sin/cos) = (cos) (1/sin) (cos/sin) = (cos/sin)2

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โˆ™ 2012-02-28 20:58:02
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Q: How do you simplify cos theta times csc theta divided by tan theta?
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