tan θ = sin θ/cos θ
tan (theta x theta) : must square the value of the angle, theta, before applying the trig function, tangent.
Yes. (Theta in radians, and then approximately, not exactly.)
It also equals 13 12.
tan(theta) = 1 then theta = tan-1(1) + n*pi where n is an integer = pi/4 + n*pi or pi*(1/4 + n) Within the given range, this gives theta = pi/4 and 5*pi/4
cot theta=tan(90-tetha)
tan2(theta) + 5*tan(theta) = 0 => tan(theta)*[tan(theta) + 5] = 0=> tan(theta) = 0 or tan(theta) = -5If tan(theta) = 0 then tan(theta) + cot(theta) is not defined.If tan(theta) = -5 then tan(theta) + cot(theta) = -5 - 1/5 = -5.2
Let x = theta, since it's easier to type, and is essentially the same variable. Since tan^2(x)=tan(x), you know that tan(x) must either be 1 or zero for this statement to be true. So let tan(x)=0, and solve on your calculator by taking the inverse. Similarly for, tan(x)=1
tan (theta x theta) : must square the value of the angle, theta, before applying the trig function, tangent.
It depends if 1 plus tan theta is divided or multiplied by 1 minus tan theta.
Cotan(theta) is the reciprocal of the tan(theta). So, cot(theta) = 1/2.
Tan theta is a function of the number theta.
Since sin(theta) = 1/cosec(theta) the first two terms simply camcel out and you are left with 1 divided by tan(theta), which is cot(theta).
Yes, it is.
4
-2(cot2theta)
Remember that tan = sin/cos. So your expression is sin/cos times cos. That's sin(theta).
The tangent function (tan) in trigonometry is defined as the ratio of the length of the opposite side to the length of the adjacent side in a right triangle. Mathematically, it can be expressed as ( \tan(\theta) = \frac{\text{opposite}}{\text{adjacent}} ). Additionally, in terms of sine and cosine, ( \tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)} ), where ( \theta ) is an angle in a right triangle or in the unit circle.