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How do you solve 2 sin squared x minus sinx minus 1 is equal to 0?
Wiki User
∙ 12y ago
2 sin(x)2 - sin(x) - 1 = 0
Let Y=sin(x) then the equation is 2*Y2 - Y - 1 =0
Delta = (-1 * -1) - 4 * 2 * -1 = 9
Y = (1 + sqrt(9)) / 4 or Y = (1 - sqrt(9)) / 4
Y = 1 or Y = -1/2
Then x = Arcsin(Y) and (in radians) x = Arcsin(1) = Pi/2 +2*k*Pi or x=Arcsin(-1/2) = -Pi/6 + 2*k*Pi
where k is an integer
Wiki User
∙ 12y ago
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(1 - csc2x)/(sinx*cotx) = -cot2x/sinxcotx = -cotx/sinx = -(cosx/sinx)/sinx = -cosx/sin2x = -cosx/(1-cos2x) = cosx/(cos2x - 1)
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How do you solve 1 minus cosx divided by sinx plus sinx divided by 1 minus cosx to get 2cscx?
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Solve 6sinx equals 1 plus 9sinx algebraically over the domain 0 is greater than or equal to x is less than 2pi?
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How do you solve 2 cos squared x - sinx - 1?
1
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How do you solve 6sin x 1 plus 9sin x algebraically over the domain 0 x 2pi?
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How do you express the term 1-csc squared x all over sin x cot x to cos x?
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