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cscx-sinx=(cosx)(cotx)
1/sinx-sinx=(cosx)(cosx/sinx)
(1/sinx)-(sin^2x/sinx)=cos^2x/sinx
cos^2x/sinx=cos^2x/sinx
Therefore LS=RS
You have to remember some trig identities when answering these questions. In this case, you need to recall that sin^2x+cos^2x=1. Also, always switch tanx cotx cscx secx in terms of sinx and cosx.
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How do you solve csc x sin x equals cos x cot x plus?
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