4x2 - 12x + 9 = 5; whence, 2x - 3 = ±√5, and 2x = 3 ±√5. Therefore, x = ½ (3 ±√5).
Factor the equation and solve for x in each part. x3-4x2-12x Factor out an x right away x (x² - 4x - 12) factor the trinomial x (x - 6) (x + 2) now solve each for y=0 x=0, (x-6=0), (x+2=0) The zeroes (solutions) to the equation are {-2 0 6 }■
It could be either of them.
If you mean: 4x squared+12x+9 then it is (2x+3)(2x+3)
4x2 - 12x + 9 = 4x2 - 6x - 6x + 9 = 2x(2x - 3) - 3(2x - 3) = (2x - 3)(2x - 3) or (2x - 3)2
4x2 = -12x, divide both sides by 4x: x = -3
4x2+12x = 4x(x+3) when factored
4x2 is 8+ 12x + 3 collect like terms, 8+3= 11, 12x+11 to solve for x, transpose the 11 to the other side of the = sign, 12x=-11, divide by 12, x=-11/12
There are four solutions to 9x4 plus 27x3 - 4x2 - 12x equals 0. One of the solutions is x = -3.
4(x + 2)(x + 1)
4x2 - 12x + 9 = 5; whence, 2x - 3 = ±√5, and 2x = 3 ±√5. Therefore, x = ½ (3 ±√5).
If you mean: 4x squared+12x-40 then it is (x+5)(x-2) after dividing all terms by 4
4x2 + 12x + 5 = (2x + 1)(2x + 5).
(√4x^2)(√36x)=2x(6√x)=12x√x
4x
Only if the value of c is 9 because:- 4x2+12x+9 = (2x+3)(2x+3)
Operational signs would make this a lot easier. Assuming that's + 12x + 5, the answer is (2x + 1)(2x + 5)