A normal 3x3 magic square has a sum of 15. So you subtract 3 from each number in the square.
The answer depends on what "this" problem is.
Every number you put in it must add up to 15 vertically, horizontally and diagonally.
There are a few ways to do it, i think. for a 3x3 board you go diagonaly up, then over right one.
A 3x3 magic square means that each row, each column, and both diagonals all have the same sum.
123 123 123
Sum = 3 x centre
Yes. One solution is: -4 16 -12 -8 0 8 12 -16 4
[ 9 ] [ 1 ] [ 6 ] [ 3 ] [ 5 ] [ 7 ] [ 4 ] [ 9 ] [ 2 ]
Excluding reflections and rotations, there is only one 3x3 magic square using 1-9.
Excluding rotations and reflections, there is only one 3x3 magic square.