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You can use the Pythagorean identity to solve this:(sin theta) squared + (cos theta) squared = 1.

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โˆ™ 2018-03-23 15:47:38
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โˆ™ 2018-04-13 17:29:27

It is +/- 0.76

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Q: If cos and theta 0.65 what is the value of sin and theta?
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Related questions

How do you simplify tan theta cos theta?

Remember that tan = sin/cos. So your expression is sin/cos times cos. That's sin(theta).


How do you simplify cos theta times csc theta divided by tan theta?

'csc' = 1/sin'tan' = sin/cosSo it must follow that(cos) (csc) / (tan) = (cos) (1/sin)/(sin/cos) = (cos) (1/sin) (cos/sin) = (cos/sin)2


De Morgan's law in complex number?

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It's 1/2 of sin(2 theta) .


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The fourth Across the quadrants sin theta and cos theta vary: sin theta: + + - - cos theta: + - - + So for sin theta < 0, it's the third or fourth quadrant And for cos theta > 0 , it's the first or fourth quadrant. So for sin theta < 0 and cos theta > 0 it's the fourth quadrant


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Let 'theta' = A [as 'A' is easier to type] sec A - 1/(sec A) = 1/(cos A) - cos A = (1 - cos^2 A)/(cos A) = (sin^2 A)/(cos A) = (tan A)*(sin A) Then you can swap back the 'A' with theta


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(/) = theta sin 2(/) = 2sin(/)cos(/)

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