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Subjects>Math>Trigonometry

If cos and theta 0.65 what is the value of sin and theta?

Anonymous

∙ 7y ago

Updated: 4/28/2022

You can use the Pythagorean identity to solve this:(sin theta) squared + (cos theta) squared = 1.

Wiki User

∙ 7y ago

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More answers

It is +/- 0.76

Wiki User

∙ 7y ago

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Q: If cos and theta 0.65 what is the value of sin and theta?

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Continue Learning about Trigonometry

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sin/cos

How do you finish the equation sin 2 theta?

(/) = theta sin 2(/) = 2sin(/)cos(/)

What is cos 360 minus theta?

Cos(360 - X) = Trig. Identity Cos(360)Cos(x) + Sin(360)Sin(x) => 1CosX + 0Sinx => CosX + o => CosX

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-0.5736

How do you work out the remaining side of a right angled triangle using theta and one side?

Suppose triangle ABC is right angled at C. Suppose you are given that the angle at B is theta. Thenif you know the length of AB (the hypotenuse), thenBC = AB*cos(theta) andAC = AB*sin(theta)if you know the length of BC, thenAB = BC/cos(theta) andAC = BC*tan(theta)if you know the length of AC, thenAB= AC/sin(theta) andBC = AC/tan(theta)

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Related Questions

How do you simplify tan theta cos theta?

Remember that tan = sin/cos. So your expression is sin/cos times cos. That's sin(theta).

How do you simplify cos theta times csc theta divided by tan theta?

'csc' = 1/sin'tan' = sin/cosSo it must follow that(cos) (csc) / (tan) = (cos) (1/sin)/(sin/cos) = (cos) (1/sin) (cos/sin) = (cos/sin)2

De Morgan's law in complex number?

(Sin theta + cos theta)^n= sin n theta + cos n theta

What is the identity for tan theta?

The identity for tan(theta) is sin(theta)/cos(theta).

What trigonometric value is equal to cos 62?

The solution is found by applying the definition of complementary trig functions: Cos (&Theta) = sin (90°-&Theta) cos (62°) = sin (90°-62°) Therefore the solution is sin 28°.

What is sin theta cos theta?

It's 1/2 of sin(2 theta) .

In which quardant are the terminal arms of the angle lie when sin thita is less then zero and cos thita is greater then zero?

The fourth Across the quadrants sin theta and cos theta vary: sin theta: + + - - cos theta: + - - + So for sin theta < 0, it's the third or fourth quadrant And for cos theta > 0 , it's the first or fourth quadrant. So for sin theta < 0 and cos theta > 0 it's the fourth quadrant

Why is 2 sin theta cos theta equal to sin 2theta?

because sin(2x) = 2sin(x)cos(x)

Prove that sin theta power 8 - cos theta power 8 equal to sin sq Theta -cos sq x 1-sin sq Theta cos sq theta?

The equation cannot be proved because of the scattered parts.

What is the derivative of sin under root theta?

The derivative of (sin (theta))^.5 is (cos(theta))/(2sin(theta))

What is the exact value of cos theta if csc theta -4 with theta in quadrant III?

csc θ = 1/sin θ → sin θ = -1/4 cos² θ + sin² θ = 1 → cos θ = ± √(1 - sin² θ) = ± √(1 - ¼²) = ± √(1- 1/16) = ± √(15/16) = ± (√15)/4 In Quadrant III both cos and sin are negative → cos θ= -(√15)/4

What is sec theta - 1 over sec theta?

Let 'theta' = A [as 'A' is easier to type] sec A - 1/(sec A) = 1/(cos A) - cos A = (1 - cos^2 A)/(cos A) = (sin^2 A)/(cos A) = (tan A)*(sin A) Then you can swap back the 'A' with theta

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