x-2=7 x=7+2
x=9
dips**t
x2 + 7x = 0 => x*(x + 7) = 0 => x = 0 or x + 7 = 0 so that x = 0 or x = -7
x=18
x2-4x-21 = 0 => x = -3 or x = 7 x2-3x-18 = 0 => x = -3 or x = 6
(2x)ysquared
144X = X2 144X - X2 = 0 (144 - X)X = 0 X = 0 or X = 144
x2 = 6482 = 64x = 8
x: x2 - 81 = 0
x2 + 3y = 7 3x + y2 = 3 3y = x2 + 7 y2 = -3x + 3 y = x2/3 + 7/3 y = ± √(-3x + 3) If you draw the graphs of y = x2/3 + 7/3 and y = ± √(-3x + 3) in a graphing calculator, you will see that they don't intersect, so that the system of the given equations has not a solution.
A quadratic equation. If you wish to solve for x, you can do so as follows: -x2 + 6x + 7 = 0 x2 - 6x - 7 = 0 (x - 7)(x + 1) = 0 x ∈ {-1, 7}
x2 + 7x = 0 => x*(x + 7) = 0 => x = 0 or x + 7 = 0 so that x = 0 or x = -7
x=18
if x2 + 7 = 37, then x2 = 29 and x = ±√29
x2-4x-21 = 0 => x = -3 or x = 7 x2-3x-18 = 0 => x = -3 or x = 6
(2x)ysquared
Factor the original equation to get (x-7)(x+2)=0, so x=7 or x=-2
Divide both sides of the equation by x: x2 = 9x x2 / x = 9x / x x = 9
144X = X2 144X - X2 = 0 (144 - X)X = 0 X = 0 or X = 144