Is it (0,25) or (25,0)? Either way, the process is the same:
y=mx+b (This is slope intercept form, m is the slope, b is a constant which you add initially when graphing)
Substitute what you know.
y=3x+b [Now put in the point that you would need to solve for b. As an example, I'll solve for (0,25) ]
25=3(0)+b
25=b Now put b back into the original, before you substituted the x and y.
y=3x+25
The y-intercept is the point where the line hits the y-axis when graphed. In order for a point to be on the y-axis, the x-value must equal zero. Therefore, substitute zero for "x" in the equation to find the y-intercept. y-intercept = (2)(0) + 5 y-intercept = 5
At what point the line intersects the y-intercept, in an equation y=mx+b, b is the y-intercept.
y=mx+b, right? So, b is the height of the y-intercept that you already have. M is the slope, rise over run. The slope is the same at all part of a line. You take the distance up from the y-intercept to the point and divide by the distance right from the y-intercept to the point. Replace m with that and you have the equation.
414
When it is a line through the origin.
The y-intercept is the point where the line hits the y-axis when graphed. In order for a point to be on the y-axis, the x-value must equal zero. Therefore, substitute zero for "x" in the equation to find the y-intercept. y-intercept = (2)(0) + 5 y-intercept = 5
The y-intercept of a linear equation is the point where the graph of the line represented by that equation crosses the y-axis.
no it is different
The y intercept is the point along the y axis at which the line (or curve) intersects. So, if your the line graphed from your equation crosses the y axis at y=1, then 1 is the y intercept. x will always be equal to zero at the y intercept, so if you plug 0 in for x and solve the equation, you get the quantity of the y intercept.
No, you need either two points, one point and a slope, one point and a y-intercept, or a y-intercept an a slope. You can also write the equation of a line with an equation of another line but you would have to know if it is parallel or perpendicular.
At what point the line intersects the y-intercept, in an equation y=mx+b, b is the y-intercept.
Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).
The point (0, -5) is the y-intercept (x = 0)
It is called the y-intercept and is the constant term in the relevant equation.
the slope of a line is 9/5 the y intercept is -4, express the equation of the line in point slope form
The x-intercept is the point where the y-intercept is zero. "3x 5y 9" is not an equation. 3x+5y+9, or 3x-5y+9, are examples of what was meant to be shown.
The slope-intercept form of the equation of a nonvertical line with slope m and y-intercept b is y = mx + b or can be expressed in function notation by replacing y with f(x), f(x) = mx + b. Functions in this form are linear functions. If a linear function is in slope-intercept form, we can use the y-intercept and the slope to obtain its graph.Graphing y = mx + b using the slope and y-intercept:1. Plot the point containing the y-intercept on the y-axis. Yhis is the point (0, b).2. Obtain a second point using the slope m. Write m as a fraction (if it is not a fraction), and use rise and run, starting at the point containing the y-intercept, to plot this point.3. Use a straightedge to draw a line through the two points (the line continues indifinetly in both directions).Example: Graph the linear functiony f(x) = -2x + 1Solution:Step 1. Find the slope m and the y-intercept.m = -2 and y-intercept is 1Step 2. Plot the point containing the y-intercept on the y-axis.Plot (0, 1)Step 3. Obtain a second point using the slope m. Write m as a fraction (if it is not a fraction), and use rise and run, starting at the point containing the y-intercept, to plot this point.m = -2/1 = Rise/RunPlot the second point by starting at (0, 1). Move 2 units down (the rise) and 1 unit to the right (the run). so we obtain a second point on the line, (1, -1).Step 4. Use a straightedge to draw a linethrough the two points.Now you have the graph of the linear function f(x) = -2x + 1.