38.42 feet.
302+482=3204 squareroot(3204) Answer=56.60388679
32.311
Pythagoras! Diagonal = sqrt (900 + 900) = 42.43'
The perimeter of a rectangle is not sufficient to determine its length.
30 ft
The diagonal is approximately 38.42 feet.
The diagonal of a rectangle with the length of 30 yd and the width of 30 yd is approximately 42.43 yd
302+482=3204 squareroot(3204) Answer=56.60388679
The diagonal will be the hypotenuse of a right triangle with legs 30 and 34 feet So its length is the square root of (34^2+ 30^2 )
32.311
The base is 24 cm x 18 cm. By Pythagoras, the diagonal of the base is sqrt(242 + 182) = sqrt(576 + 324) = sqrt(900) = 30 cm
"X" = .66
That would be 34 feet.
Since the rectangle has right angles, you can use Pythagoras' Theorem in this case.
Assuming that the 40 and 30 refer to sides of a rectangle and not to any of the infinite number of other possible shapes, the answer is 50.
You can calculate this using the Pythagorean formula for a right triangle.
A square with a 30-inch diagonal measurement has sides of 21.21 inches in length.