Oh, dude, you're hitting me with the math questions now? Okay, okay, let me think. So, the diagonal of a rectangle can be found using the Pythagorean theorem, right? So, it's like the square root of (24 squared + 30 squared). That's like 36 feet. So, the diagonal of a 24 ft by 30 ft rectangle is 36 feet.
302+482=3204 squareroot(3204) Answer=56.60388679
32.311
Pythagoras! Diagonal = sqrt (900 + 900) = 42.43'
The perimeter of a rectangle is not sufficient to determine its length.
30 ft
The diagonal is approximately 38.42 feet.
The diagonal of a rectangle with the length of 30 yd and the width of 30 yd is approximately 42.43 yd
302+482=3204 squareroot(3204) Answer=56.60388679
The diagonal will be the hypotenuse of a right triangle with legs 30 and 34 feet So its length is the square root of (34^2+ 30^2 )
To find the diagonal of a rectangle, you can use the Pythagorean theorem. For a rectangle with dimensions 30 ft and 48 ft, the diagonal (d) can be calculated using the formula (d = \sqrt{(30^2 + 48^2)}). This gives (d = \sqrt{(900 + 2304)} = \sqrt{3204} \approx 56.6) ft. Therefore, the diagonal is approximately 56.6 feet long.
The base is 24 cm x 18 cm. By Pythagoras, the diagonal of the base is sqrt(242 + 182) = sqrt(576 + 324) = sqrt(900) = 30 cm
32.311
"X" = .66
To find the diagonal measurement of a rectangle, you can use the Pythagorean theorem. For a rectangle with sides of 30 feet and 32 feet, the diagonal (d) can be calculated as (d = \sqrt{30^2 + 32^2}). This gives (d = \sqrt{900 + 1024} = \sqrt{1924}), which simplifies to approximately 43.9 feet.
That would be 34 feet.
Since the rectangle has right angles, you can use Pythagoras' Theorem in this case.
To find the diagonal of a rectangle with dimensions 15 and 30, you can use the Pythagorean theorem. The diagonal ( d ) is calculated as ( d = \sqrt{(15^2 + 30^2)} ). This results in ( d = \sqrt{(225 + 900)} = \sqrt{1125} ), which simplifies to ( d \approx 33.54 ). Thus, the diagonal of a 15x30 rectangle is approximately 33.54 units.