32.311
The diagonal of 132 x 132 is: 186.7
That would be ...(242 + 302)-2 = 38.42(Thank you, Mr Pythagoras)
Let the other diagonal be x If: 0.5*12*x = 30 then x = 60/12 => x = 5 The rhombus has four interior right angle triangles with lengths of 6 cm and 2.5 cm Using Pythagoras each equal sides of the rhombus works out as 6.5 cm Perimeter: 4*6.5 = 26 cm
The diagonal of a square = the length of one side x the square root of 2 (approx 1.414)
The diagonal of a 30' x 30' square is: 42.43 feet.
32.311
appx. 30' 4.9"
That would be 34 feet.
"X" = .66
The diagonal of 132 x 132 is: 186.7
A 9 x 12 rectangle has a diagonal of 15.
The diagonal is 15.652'
The diagonal of a rectangle with the length of 30 yd and the width of 30 yd is approximately 42.43 yd
The diagonal is 69.856 feet.
The answer depends on the angle between the 9 ft length and the 21 ft length.If the angle between the two is x, then(diagonal)2 = [9 + 21cos(x)]2 + [21sin(x)]2 = 522 + 378*cos(x).Therefore, 522-378 ≤ diagonal2 ≤ 522 + 378that is 144 ≤ diagonal2 ≤ 900or 12 ≤ diagonal ≤ 30
A square with a 30-inch diagonal measurement has sides of 21.21 inches in length.