32.311
302+482=3204 squareroot(3204) Answer=56.60388679
Oh, dude, you're hitting me with the math questions now? Okay, okay, let me think. So, the diagonal of a rectangle can be found using the Pythagorean theorem, right? So, it's like the square root of (24 squared + 30 squared). That's like 36 feet. So, the diagonal of a 24 ft by 30 ft rectangle is 36 feet.
Pythagoras! Diagonal = sqrt (900 + 900) = 42.43'
That would be ...(242 + 302)-2 = 38.42(Thank you, Mr Pythagoras)
The rectangle has a length of 12 cm and a width of 3 cm.
That would be 34 feet.
To find the diagonal measurement of a rectangle, you can use the Pythagorean theorem. For a rectangle with sides of 30 feet and 32 feet, the diagonal (d) can be calculated as (d = \sqrt{30^2 + 32^2}). This gives (d = \sqrt{900 + 1024} = \sqrt{1924}), which simplifies to approximately 43.9 feet.
Since the rectangle has right angles, you can use Pythagoras' Theorem in this case.
Assuming that the 40 and 30 refer to sides of a rectangle and not to any of the infinite number of other possible shapes, the answer is 50.
To find the diagonal measurement of a rectangle with dimensions 80 feet by 30 feet, you can use the Pythagorean theorem. The diagonal ( d ) is calculated as ( d = \sqrt{(80^2 + 30^2)} ). This results in ( d = \sqrt{(6400 + 900)} = \sqrt{7300} ), which is approximately 85.0 feet.
The diagonal of a rectangle with the length of 30 yd and the width of 30 yd is approximately 42.43 yd
Use Pythagoras' theorem:- 502+302 = 3400 and the square root of this is the length of the diagonal which is about 58.309 feet to 3 dp
The diagonal is approximately 38.42 feet.
A square with a 30-inch diagonal measurement has sides of 21.21 inches in length.
To find the diagonal of a rectangle with dimensions 15 and 30, you can use the Pythagorean theorem. The diagonal ( d ) is calculated as ( d = \sqrt{(15^2 + 30^2)} ). This results in ( d = \sqrt{(225 + 900)} = \sqrt{1125} ), which simplifies to ( d \approx 33.54 ). Thus, the diagonal of a 15x30 rectangle is approximately 33.54 units.
The diagonal will be the hypotenuse of a right triangle with legs 30 and 34 feet So its length is the square root of (34^2+ 30^2 )
302+482=3204 squareroot(3204) Answer=56.60388679
Oh, dude, you're hitting me with the math questions now? Okay, okay, let me think. So, the diagonal of a rectangle can be found using the Pythagorean theorem, right? So, it's like the square root of (24 squared + 30 squared). That's like 36 feet. So, the diagonal of a 24 ft by 30 ft rectangle is 36 feet.
To find the diagonal of a rectangle, you can use the Pythagorean theorem. For a rectangle with dimensions 30 ft and 48 ft, the diagonal (d) can be calculated using the formula (d = \sqrt{(30^2 + 48^2)}). This gives (d = \sqrt{(900 + 2304)} = \sqrt{3204} \approx 56.6) ft. Therefore, the diagonal is approximately 56.6 feet long.
In a rectangle, the perpendicular measurement refers to the height or width when considering the length as one dimension. For a rectangle measuring 26 feet in width and 30 feet in length, the perpendicular measurement can be either 26 feet (width) or 30 feet (length), depending on the orientation. If you are referring to the height of a rectangle, it typically is not defined unless specified as a 3D object.
You can calculate this using the Pythagorean formula for a right triangle.
To find the length of the diagonal of a rectangle, we can use the Pythagorean theorem, which states that the square of the length of the diagonal is equal to the sum of the squares of the lengths of the two sides. In this case, the diagonal length (d) can be calculated as follows: d^2 = 30^2 + 50^2. Therefore, d^2 = 900 + 2500 = 3400. Taking the square root of 3400 gives us the diagonal length, which is approximately 58.3 feet.
It very much depends on what z is.
"X" = .66
12+12+3+3= 30 so perimeter is 30