38.42 feet.
302+482=3204 squareroot(3204) Answer=56.60388679
Pythagoras! Diagonal = sqrt (900 + 900) = 42.43'
That would be ...(242 + 302)-2 = 38.42(Thank you, Mr Pythagoras)
The rectangle has a length of 12 cm and a width of 3 cm.
That would be 34 feet.
Since the rectangle has right angles, you can use Pythagoras' Theorem in this case.
Assuming that the 40 and 30 refer to sides of a rectangle and not to any of the infinite number of other possible shapes, the answer is 50.
The diagonal of a rectangle with the length of 30 yd and the width of 30 yd is approximately 42.43 yd
Use Pythagoras' theorem:- 502+302 = 3400 and the square root of this is the length of the diagonal which is about 58.309 feet to 3 dp
The diagonal is approximately 38.42 feet.
38.42 feet.
A square with a 30-inch diagonal measurement has sides of 21.21 inches in length.
The diagonal will be the hypotenuse of a right triangle with legs 30 and 34 feet So its length is the square root of (34^2+ 30^2 )
302+482=3204 squareroot(3204) Answer=56.60388679
You can calculate this using the Pythagorean formula for a right triangle.
To find the length of the diagonal of a rectangle, we can use the Pythagorean theorem, which states that the square of the length of the diagonal is equal to the sum of the squares of the lengths of the two sides. In this case, the diagonal length (d) can be calculated as follows: d^2 = 30^2 + 50^2. Therefore, d^2 = 900 + 2500 = 3400. Taking the square root of 3400 gives us the diagonal length, which is approximately 58.3 feet.