The diagonal is 8.602 cm
Using Pythagoras the length of the diagonal in the rectangle is the square root of 149 or just over 12 cm
7 X 2 = 14 6 X 2 = 12 12 + 14 = 26 ----
2 (x + 2x) = 42 x + 2x = 21 3x = 21 Therefore, x = 7 The width of the rectangle is 7 inches. The length of the rectangle is 14 inches.
Area of rectangle: 9 times 7 = 63 square meters
6x-14
The diagonal is 8.602 cm
You use the pythagorous theorm to calculate the hypotenuse of the triangle, which is the same line as the diagonal. 7(7)+ 10(10)= diagonal x diagonal 149= diagonal x diagonal Diagonal= square root of 149: this approximates to 12.207in Visit quickanswerz.com for more math help/tutoring! Consider a rectangle with dimensions 7 inches by 10 inches. Let ABCD be the rectangle. We need to find the length of the diagonal. We know that the diagonals of a rectangle are same in length. So, it is enough to find the length of the diagonal BD. From the rectangle ABCD, it is clear that the triangle BCD is a right angled triangle. So, we can find the length of the diagonal using the Pythagorean Theorem. BD2 = BC2 + DC2 BD2 = 102 + 72 BD2 = 100 + 49 BD2 = 149 BD = √149 BD = 12.207 So, the length of the diagonal is 12.21 inches. Source: www.icoachmath.com
A = 168 in2
14 sq. inches
Good old Arthur. There is a Pythagorean triple (5-12-13) lurking in this question. Diagonal is 26 cm making x = 7
It depends on what the 7' and 10' refers to. They could be adjacent sides of a rectangle or a parallelogram. If the latter, more information is required before the question can be answered.
7 feet 2(7+2) = 18 feet 7*2 = 14 square feet
Using Pythagoras the length of the diagonal in the rectangle is the square root of 149 or just over 12 cm
98
The perimeter is 18 feet.
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