I am assuming you mean 3-number combinations rather than 3 digit combinations. Otherwise you have to treat 21 as a 2-digit number and equate it to 1-and-2.
There are 21C3 combinations = 21*20*19/(3*2*1) = 7980 combinations.
There are 5,461,512 such combinations.
There are 1140 5 digit combinations from 1 to 20. 20 combination 3 computes that.
Assuming the digits cannot be repeated, there are 7 combinations with 1 digit, 21 combinations with 2 digits, 35 combinations with 3 digits, 35 combinations with 4 digits, 21 combinations with 5 digits, 7 combinations with 6 digits and 1 combinations with 7 digits. That makes a total of 2^7 - 1 = 127: too many for me to list. If digits can be repeated, there are infinitely many combinations.
100
44
There are 1140 five digit combinations between numbers 1 and 20.
Just 1.
The answer will depend on how many digits there are in each of the 30 numbers. If the 30 numbers are all 6-digit numbers then the answer is NONE! If the 30 numbers are the first 30 counting numbers then there are 126 combinations of five 1-digit numbers, 1764 combinations of three 1-digit numbers and one 2-digit number, and 1710 combinations of one 1-digit number and two 2-digit numbers. That makes a total of 3600 5-digit combinations.
7
100
How many four digit combinations can be made from the number nine? Example, 1+1+2+5=9.
44
Using the eight digits, 1 - 8 ,-- There are 40,320 eight-digit permutations.-- There is 1 eight-digit combination.
120 combinations using each digit once per combination. There are 625 combinations if you can repeat the digits.
There are 167960 9 digits combinations between numbers 1 and 20.
Any 5 from 59 = 5006386
1296 or (6^4)