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Q: How many 4 digit combinations can you get from numbers 1226?

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Number of 7 digit combinations out of the 10 one-digit numbers = 120.

The answer will depend on how many digits there are in each of the 30 numbers. If the 30 numbers are all 6-digit numbers then the answer is NONE! If the 30 numbers are the first 30 counting numbers then there are 126 combinations of five 1-digit numbers, 1764 combinations of three 1-digit numbers and one 2-digit number, and 1710 combinations of one 1-digit number and two 2-digit numbers. That makes a total of 3600 5-digit combinations.

There are 38760 combinations.

There are 1140 five digit combinations between numbers 1 and 20.

There are 9 1-digit numbers and 16-2 digit numbers. So a 5 digit combination is obtained as:Five 1-digit numbers and no 2-digit numbers: 126 combinationsThree 1-digit numbers and one 2-digit number: 1344 combinationsOne 1-digit numbers and two 2-digit numbers: 1080 combinationsThat makes a total of 2550 combinations. This scheme does not differentiate between {13, 24, 5} and {1, 2, 3, 4, 5}. Adjusting for that would complicate the calculation considerably and reduce the number of combinations.

There are 840 4-digit combinations without repeating any digit in the combinations.

7

56 combinations. :)

How many numbers are there between 0000 and 9999?

Any 6 from 51 = 18,009,460 combinations

5

45.

There are 167960 9 digits combinations between numbers 1 and 20.

There are 167960 9 digits combinations between the numbers 1 and 20.

120 combinations using each digit once per combination. There are 625 combinations if you can repeat the digits.

There would be 9*9*9*9 or 6561 combinations.

If the numbers are not allowed to repeat themselves then 362,880. * * * * * That is the number of permutations, not combinations. In a combination the order of the digits does not matter. So there is only one 9-digit combination.

90

If there are no restrictions on duplicated numbers or other patterns of numbers then there are 10 ways of selecting the first digit and also 10 ways of selecting the second digit. The number of combinations is therefore 10 x 10 = 100.

There are 9C2 = 9*8/(2*1) = 36 2-digit combinations.

how many combinations of 4 numbers are there in 7 numbers

5 digit combinations for numbers 1 to 50= 50 C 5N!= 1x2x3x4x...x (N-1) x N= (50!)/(45!x5!) =(50x49x...x2x1)/((45x44x...x2x1)(5x4x3x2x1))=(50x49x48x47x46)/(5x4x3x2)=254251200/120 =21187602118760 combinations

-8

Exactly 3,628,800, or 10!.

10!/3! = 604800 different combinations.