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Q: How many 5 digit combinations are in 12345?

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There are 126 different 5 digit combinations. Note that the combination 12345 is the same as the combination 45312.

12345, 23451, 34512, 45123, 51234 lol easy

There are 5,461,512 such combinations.

There are 1140 5 digit combinations from 1 to 20. 20 combination 3 computes that.

There are 1140 five digit combinations between numbers 1 and 20.

about 1,0000000000000

105 = 100000

120 5-digit numbers can be made with the numbers 12345.

100

12345

It depends on how many digit you are choosing from.

Any 5 from 59 = 5006386

5

5 ^12

The answer will depend on how many digits there are in each of the 30 numbers. If the 30 numbers are all 6-digit numbers then the answer is NONE! If the 30 numbers are the first 30 counting numbers then there are 126 combinations of five 1-digit numbers, 1764 combinations of three 1-digit numbers and one 2-digit number, and 1710 combinations of one 1-digit number and two 2-digit numbers. That makes a total of 3600 5-digit combinations.

90

There would be 9*9*9*9 or 6561 combinations.

If no digit can be repeated then there are 5 combinations, abcd, abce, abde, acde and bcde. If you regard abdc as different from abcd then each of the 5 basic sets could be arranged 24 ways and the total would be 120 combinations.

The number of four-digit combinations is 10,000 .Stick a '3' before each of them, and you have all the possible 5-digit combinations that start with 3.There are 10,000 of them. They run from 30,000 to 39,999 .

How many four digit combinations can be made from the number nine? Example, 1+1+2+5=9.

90000. With 10 digit palindromes, the last 5 digits are the same as the first 5 digits in reverse, eg 12345 54321. So it comes down to how many 5 digit numbers are there? They are the numbers "10000" to "99999", a total of 99999 - 10000 + 1 = 90000.

50 to the 5th power.156,250 combination.

4+4+4+4+4= 20

int num = 12345; int lastDigit = num % 10; // = 5

For the first digit you have 5 options, whichever you choose for the first digit, you have 4 options for the second digit, etc.; so the number of combinations is 5 x 4 x 3 x 2.For the first digit you have 5 options, whichever you choose for the first digit, you have 4 options for the second digit, etc.; so the number of combinations is 5 x 4 x 3 x 2.For the first digit you have 5 options, whichever you choose for the first digit, you have 4 options for the second digit, etc.; so the number of combinations is 5 x 4 x 3 x 2.For the first digit you have 5 options, whichever you choose for the first digit, you have 4 options for the second digit, etc.; so the number of combinations is 5 x 4 x 3 x 2.