4+4+4+4+4= 20
There are 1140 five digit combinations between numbers 1 and 20.
There are 60C5 = 60!/(5!(60-5)!) = 60 × 59 × 58 × 57 × 56 / (5 × 4 × 3 × 2 × 1) = 5,461,512 There are 5,461,512 possible combinations of 5 numbers from 1-60.
The answer will depend on how many digits there are in each of the 30 numbers. If the 30 numbers are all 6-digit numbers then the answer is NONE! If the 30 numbers are the first 30 counting numbers then there are 126 combinations of five 1-digit numbers, 1764 combinations of three 1-digit numbers and one 2-digit number, and 1710 combinations of one 1-digit number and two 2-digit numbers. That makes a total of 3600 5-digit combinations.
There are: 17C5 = 6188
90
4+4+4+4+4= 20
Possible 5 digit combinations using 5 digits only 1 time is 5! or 5*4*3*2*1 or 120. Using 5 digits where numbers can be used 5 times is 55 or 3125.
The number of four-digit combinations is 10,000 .Stick a '3' before each of them, and you have all the possible 5-digit combinations that start with 3.There are 10,000 of them. They run from 30,000 to 39,999 .
There are 5,461,512 such combinations.
There are 1140 5 digit combinations from 1 to 20. 20 combination 3 computes that.
6,720 combinations.
There are 1140 five digit combinations between numbers 1 and 20.
it depends on which 8 numbers your talking about
Just 1.
about 1,0000000000000
If the same 7 digits are used for all the combinations then n! = 7! = 7*6*5*4*3*2*1 = 5040 combinations There are 9,999,999-1,000,000+1=9,000,000 7-digit numbers.