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You would use combinations instead of permutations so just type in your calculator 96667C5 and you should get 70333953523652148234618

Or, you could use the formula...

r=number chosen

n=number to chose from

n!/((n-r)!(r!))

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If the question was meant to ask - How many 5 number combinations (actually,

permutations) can be made from (the digits) 9,6,6,6,7 ? - The answer would be:

2(5C2) = 2[5!/(3!2!)] = 20

i.e., 96676, 96766, 97666, ...

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12y ago

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