You would use combinations instead of permutations so just type in your calculator 96667C5 and you should get 70333953523652148234618
Or, you could use the formula...
r=number chosen
n=number to chose from
n!/((n-r)!(r!))
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If the question was meant to ask - How many 5 number combinations (actually,
permutations) can be made from (the digits) 9,6,6,6,7 ? - The answer would be:
2(5C2) = 2[5!/(3!2!)] = 20
i.e., 96676, 96766, 97666, ...
If repeats are allowed than an infinite number of combinations is possible.
You Can Create 999 Number combinations
6 of them.
4*3*2*1 = 24 different combinations.
2 to the 7th power = 128 * * * * * No. That is the total number of combinations, consisting of any number of elements. The number of 2 number combinations is 7*6/2 = 21
How many four digit combinations can be made from the number nine? Example, 1+1+2+5=9.
8C6 = 28
9!/5! or 3024
If every number can be used as many times as you like, there are 104 = 10000 different combinations. If each number can only be used once, there are 9!/(9 - 4)! = 5040 combinations.
Since a number can have infinitely many digits, there are infinitely many possible combinations.
The number of combinations of six numbers that can be made from seven numbers will depend on if you can repeat numbers. In all there are over 2,000 different numbers that can be made.
Only 1. In a combination, the order of the digits does not matter.