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Micron: wished you had posted the logic. As I see it, the first can be one of 8 digits. The second number can be 0 or 1 but not the same as the first (9 to choose from). The third cannot be the same as either of the first two (8 to choose from), etc. Thus it would be 8*9*8*7*6*5*4=483,840

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Q: How many 7 digit phone numbers are available if a digit can only be used once and the first number can not be 0 or 1?
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