The specific heat of water is 1 BTU per pound per degree Fahrenheit. There are 8.3378 lbs/gallon at 60 degrees, which equals 3251.742 pounds of water. The number of BTUs to raise it 188 degrees is then 611,327.496 BTUs.
89,964 Btu's in 60 Gallons of water. Here's the formula. Gallons times maximum temperature rise times weight of one gallon equals Btus. In the example, Gallons = 60 Max temp rise = 180°F or from freezing to boiling, 212°F minus 32°F weight of one gallon = 8.33 lb 60 x 180 x 8.33 = 89,964
The question cannot be answered because:the temperature scale being used has not been specified,There is no normal temperature scale in which you can have ice at 32 degrees and steam at 82 degrees without large changes in pressure. If changes in pressure are permitted then there is no simple formula to calculate the amount of heat (btus) required.
depends on the amount of water
Out
depends how big the heating source is
To answer this question we would need to know the BTUs of the hot plate, the area of the hotplate's surface, the interconnecting area of the hotplates surface and the water container. The Heat capacity of water we can get from a reference book.
You would need to remove approximately 1200 BTUs of heat to convert a gallon of water to ice. There are 8.34 lb in a gallon of water, which converting to lb-moles is 0.463. The latent heat of crystallization for water is -2583.4 BTU/lb-mole. Multiplying the two together and you get -1197 BTUs, which means you need to remove that amount of heat to convert the gallon of water to ice.
170o
100 BTU if it's Fahrenheit
One measure does not directly translate to another. A BTU is the amount of heat that it takes to raise the temp of one pound of water by one degree F. A burning match, and a burning fireplace may both be at 650 degrees, but the fireplace gives off more heat (more BTUs)
That depends on what the starting temperature of the water is,and what temperature you want it to reach.If you expect to get a number, you must first give the necessary numbers.
no
1)This is a 5 part question. The first is realizing that 20F to 32F uses .5BTU per pound per degree. That means it takes 32-20=12*.5=6BTUs to get the ice to 32F. 2)Then you need to know the Latent Heat of Fusion for Ice which is 144BTUs (given). Lets assumes the ice changes from ice to water instantaneously at 32F. 3)Next we calculate the BTUs from 32F to 212F. Which is 1BTU per pound per degree F. 212-32=180 so it take 180BTUS. 4)Next we have to use the Latent Heat of Vaporization of water which will say instantaneously converts water to vapor. This takes 970BTUS (given). 5)Then we calculate the BTUS from 212F to 220F. Which is .5BTUs per pound per degree F which is 220-212=8*.5=4BTUs...... Finally add up all the BTUs and you get 6+144+180+970+4=1304BTUs.
heat will flow from the iron to the water until both are the same temperature
None. Changing water from 25 degrees C to 5 degrees C requires heat to be REMOVED, not added!
212 - 80 = 132 degrees temperature increase x 1 pound water = 132 BTU
That depends on the starting temperature of the cold water and the starting temperature of the hot water.
BTU is an abbreviation for British Thermal Unit. This represents how much heat or energy is required to increase the temperature of 1 lb of water by 1 degree Fahrenheit. Gasoline, on average, creates between 115,000 and 125,000 BTUs. In contrast, ethanol creates about 75,000 BTUs.